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3 years ago

It took 500N of force to push a car 4 meters. how much work is done?

Chemistry

1 answer:

Agata [3.3K]3 years ago

7 0

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 500 × 4

We have the final answer as

Hope this helps you

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The water cycle always follows the same pattern

strojnjashka [21]

If it is a true or false questions, the answer is TRUE.

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3 years ago

Read 2 more answers

. How many grams of water would require 4400 joules

Alja [10]

Answer:

The specific heat of water is 4.18 J/g C.

Explanation:

Never forget that!

2200

⋅

4.18

⋅

∴

≈

8.0

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2 years ago

HELP!!!! A glass flask containing 100 milliliters of water is sealed with a rubber stopper and placed on a burner. After a while

kondor19780726 [428]

Answer: A closed system, because energy can enter or leave the container, but the water molecules cannot

Explanation:

Open system: In this system energy and matter both have access to their surroundings beyond the boundaries of system. .

Closed system :In this type system only energy has an access to its surroundings beyond the boundaries of system but not matter.

Isolated system:In this type system exchange of both energy and matter are restricted to move outside the boundaries of system.

According to question, the system given is a closed system because energy is transferred from the burner to glass flask and from the glass flask to the water (matter). But water molecules are only getting condensed on the inside surface of the flask that is exchange of matter beyond the boundaries of the system is restricted. Hence, closed system ,A closed system, because energy can enter or leave the container, but the water molecules cannot.

7 0

2 years ago

How many moles in 2.21 x10E24 atoms of aluminum

lisov135 [29]

<h3>Answer:</h3>

3.67 mol Al

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.21 × 10²⁴ atoms Al

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 2.21 \cdot 10^{24} \ atoms \ Al(\frac{1 \ mol \ Al}{6.022 \cdot 10^{23} \ atoms \ Al})$
Divide: $\displaystyle 3.66988 \ mol \ Al$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.66988 mol Al ≈ 3.67 mol Al

7 0

2 years ago

The flask contains 10.0 mL 10.0 mL of HCl HCl and a few drops of phenolphthalein indicator. The buret contains 0.130 M NaOH . 0.

Lyrx [107]

The question is incomplete, here is the complete question:

The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.130 M NaOH. It requires 32.4 mL of the NaOH solution to reach the end point of the titration. What is the concentration of HCl ?

<u>Answer:</u> The concentration of HCl is 0.421 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=10.0mL\\n_2=1\\M_2=0.130M\\V_2=32.4mL$

Putting values in above equation, we get:

$1\times M_1\times 10.0=1\times 0.130\times 32.4\\\\M_1=\frac{1\times 0.130\times 32.4}{1\times 10.0}=0.421M$

Hence, the concentration of HCl is 0.421 M

8 0

3 years ago