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3 years ago

It took 500N of force to push a car 4 meters. how much work is done?

Chemistry

1 answer:

Agata [3.3K]3 years ago

7 0

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 500 × 4

We have the final answer as

Hope this helps you

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Please answer, this is due in 30 minutes

notsponge [240]

Answer:

0.591 g of magnesium phosphate is the theoretical yield.

Magnesium nitrate is the limiting reactant.

Explanation:

Hello!

In this case, since the balanced reaction turns out:

$3Mg(NO_3)_2+2Na_3PO_4\rightarrow Mg_3(PO_4)_2+6NaNO_3$

Next, we compute the grams of magnesium phosphate yielded by each reactant, considering the present mole ratios and molar masses:

$m_{Mg_3(PO_4)_2}^{by\ Mg(NO_3)_2}=1.00gMg(NO_3)_2*\frac{1molMg(NO_3)_2}{148.31gMg(NO_3)_2}*\frac{1molMg_3(PO_4)_2}{3molMg(NO_3)_2} *\frac{262.86gMg_3(PO_4)_2}{1molMg_3(PO_4)_2} \\\\m_{Mg_3(PO_4)_2}^{by\ Mg(NO_3)_2}= 0.591gMg_3(PO_4)_2\\\\m_{Mg_3(PO_4)_2}^{by\ Na_3PO_4}=1.00gNa_3PO_4*\frac{1molNa_3PO_4}{163.94gNa_3PO_4}*\frac{1molMg_3(PO_4)_2}{2molNa_3PO_4} *\frac{262.86gMg_3(PO_4)_2}{1molMg_3(PO_4)_2} \\\\m_{Mg_3(PO_4)_2}^{by\ Na_3PO_4} = 0.802gMg_3(PO_4)_2$

Thus, we infer that the correct theoretical yielded mass is 0.591 g as magnesium nitrate is the limiting reactant for which it produces the fewest grams of product.

However, is not possible to compute the percent yield since no actual yield is given, and must be provided or indicated by the problem or an experiment and it not here, nevertheless, you may compute the percent yield by dividing the actual yield by the theoretical and then multiplying by 100:

$Y=\frac{actual}{0.591g}*100\%$

Best regards!

4 0

3 years ago

Would you expect the actual yield to be larger or smaller than the theoretical yield? Explain.

docker41 [41]

Smaller, there are many human and systematic errors that can alter the amount of product that can be obtained.

3 0

3 years ago

An example of a scientific law is the law of conservation of mass, which states that matter is neither created nor destroyed in

svp [43]

Explanation:

According to the law of conservation of mass, it makes a generalized observation that there will occur no change in the mass of a substance even if it undergoes a chemical reaction.

Whereas this law of conservation does not explain any phenomenon of why this conservation of mass occurs.

Therefore, the given statements are classified as follows.

A) It was developed from past observations - Ture

B) It is subject to experimentation and revision - True

C) It explains why mass is conserved - False

D) It predicts future observations - True

4 0

4 years ago

Calculate the volume of 1.0 x 10-4 M CV+ solution that needs to be added to a 25.0 mL volumetric flask and diluted with deionize

xenn [34]

Answer:

The answers are: 2.5 ml (first part) and 3.0 ml (second part)

Explanation:

In order to calculate volumes required to prepare diluted solutions we use the following equation:

Vc x Cc = Vd x Cd

Where Vc and Cc are the volume and concentration respectively of concentrated solution (higher concentration) whereas Vd and Cd are volume and concentration of diluted solution (lower concentration).

In both problems we want to prepare a diluted solution and we know the final concentration (Cd) and final volume (Vd) and the initial concentration (Cc).

In first part, we have: Cc= 1.0 10⁻⁴ M; Vd= 25 ml; Cd= 1.0 10⁻⁵ M

Vc= Vd x Cd / Cc= (25 ml x 1.0 10⁻⁵ M)/1.0 10⁻⁴ M = 2.5 ml

Notice that Cc/Cd= 1.0 10⁻⁴ M/Cd= 1.0 10⁻⁵ M= 10 (so, we have to dilute the solution 10 times, and for this we have to take a volume 10 times lower than the final volume).

To prepare the solution, we take 2.5 ml of 1.0 10⁻⁵ M CV+, we dispense the volume in a 25 ml volumetric flask and then we add water until complete 25 ml (aproximately 22.5 ml of water).

In the second part is the same. We have: Vd= 10 ml; Cc= 1.0 10⁻⁴M; Cd= 3.0 10⁻⁵M.

Vc= Vd x Cd / Cc= (10 ml x 3.0 10⁻⁵ M)/1.0 10⁻⁴ M = 3 ml

To prepare the solution, we take 3 ml of 3.0 10⁻⁵ M CV+, we dispense the volume in a 10 ml volumetric flask and then we add water until we complete 10 ml (aproximately 7 ml of water).

6 0

3 years ago

On July 8th, I will be 8.51472x10^8 seconds old. How old will I be in years? (Assume 365 days in a year.) Group of answer choice

KatRina [158]

Answer:

26.98

almost 27 years

5 0

3 years ago