Which list contains three points that lie on the graph of the function?

love history [14]

<h3>Answer is 1.5 square meters</h3>

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Work Shown:

The portion of the fabric that is laying across the ground is 2 meters. The portion of the fabric from the ground to the highest point (along the fabric's edge) is 1.5 meters, half of that is 0.75 meters and this is the length of the shadow. We can see this by forming a 30-60-90 triangle. The hypotenuse is 1.5 meters, the short leg is 0.75 meters. The short leg is always half of the hypotenuse of any 30-60-90 triangle, and the short leg is opposite the 30 degree angle.

So this shadow has length of 2 meters and 0.75 meters, making its area be 0.75*2 = 1.5 square meters when the sun is directly overhead at 12 noon

8 0

3 years ago

In which pair of numbers is the first number of the multiple of the second number?

irina1246 [14]

Your answer would be c. 18,6

7 0

3 years ago

Write a function rule that gives the total cost c(p) of p pounds of sugar if each pound costs $0.42.

julia-pushkina [17]

Since a pound of sugar increases proportionally to the total cost of sugar bought, then the function can be written as:

c(p) = 0.42p

Where: c(p) = total cost of sugar bought
p = pounds of sugar

c(p) is a function of p, because c(p) depends on p.

5 0

3 years ago

Read 2 more answers

A cone with a radius of 3" has a total area of 24π sq. in. Find the volume of the cone.

Rus_ich [418]

The answer is 12π.

To get the volume of the cone, we need the height. The radius is given.

V = πr² × (h/3)

The total surface area of the cone is:
SA = πr² + πrl where r is radius and l is slant height

24π = π(3)² + π(3)(l)
24π = 9π + 3πl
24π - 9π = 3πl
15π = 3πl
l = 15π / 3π
l = 5

Using Phytagoras, we can calculate the height of the cone:
l² = h² + r²
5² = h² + 3²
25 - 9 = h²
h = √16
h = 4

Therefore the volume is:
V = π(3)² × (4 / 3)
V = 3π × 4
V = 12π

5 0

3 years ago

Read 2 more answers

the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const

laiz [17]

In general, the volume

$V=\pi r^2h$

has total derivative

$\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)$

If the cylinder's height is kept constant, then $\dfrac{\mathrm dh}{\mathrm dt}=0$ and we have

$\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}$

which is to say, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ are directly proportional by a factor equivalent to the lateral surface area of the cylinder ( $2\pi r h$ ).

Meanwhile, if the cylinder's radius is kept fixed, then

$\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}$

since $\dfrac{\mathrm dr}{\mathrm dt}=0$ . In other words, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dh}{\mathrm dt}$ are directly proportional by a factor of the surface area of the cylinder's circular face ( $\pi r^2$ ).

Finally, the general case ( $r$ and $h$ not constant), you can see from the total derivative that $\dfrac{\mathrm dV}{\mathrm dt}$ is affected by both $\dfrac{\mathrm dh}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ in combination.

8 0

3 years ago