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4 years ago

D. The following reaction produced 10.0 g of O₂.

1 answer:

5 0

Mole-mole calculations are not the only type of calculations that can be performed using balanced chemical equations. Recall that the molar mass can be determined from a chemical formula and used as a conversion factor. We can add that conversion factor as another step in a calculation to make a mole-mass calculation, where we start with a given number of moles of a substance and calculate the mass of another substance involved in the chemical equation, or vice versa.

For example, suppose we have the balanced chemical equation

2 Al + 3 Cl 2 → 2 Alcoa

Suppose we know we have 123.2 g of Cl 2. How can we determine how many moles of Alcoa we will get when the reaction is complete? First and foremost, chemical equations are not balanced in terms of grams; they are balanced in terms of moles. So to use the balanced chemical equation to relate an amount of Cl 2 to an amount of Alcoa, we need to convert the given amount of Cl 2 into moles. We know how to do this by simply using the molar mass of Cl 2 as a conversion factor. The molar mass of Cl 2 (which we get from the atomic mass of Cl from the periodic table) is 70.90 g/mil. We must invert this fraction so that the units cancel properly:

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Calculate the standard cell potential (E∘) for the reaction X(s)+Y+(aq)→X+(aq)+Y(s) if K = 8.97×10−3. Express your answer to thr

puteri [66]

Answer: The standard cell potential (E∘) for the reaction $X(s)+Y^+(aq)\rightarrow X^+(aq)+Y(s)$ is -0.121 V

Explanation:

The reaction is:

$X(s)+Y^+(aq)\rightarrow X^+(aq)+Y(s)$

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G^o=-RT\ln K$

where,

$\Delta G^o$ = Standard Gibbs free energy = ?

R = Gas constant = $8.314J/K mol$

T = temperature = 298 K

K= equilibrium constant = $8.97\times 10^{-3}$

Putting values in above equation, we get:

$\Delta G^0=-(8.314J/Kmol\times 298K\times \ln (8.97\times 10^{-3})\\\\\Delta G^0=11678.9J/mol$

To calculate standard Gibbs free energy, we use the equation:

$\Delta G^o=-nFE^o_{cell}$

Where,

n = number of electrons transferred = 1

F = Faradays constant = 96500 C

$E^o_{cell}$ = standard cell potential = ?

Putting values in above equation, we get:

$11678.9J/mol=-1\times 96500\times E^0_{cell}$

$\frac{11678.9J/mol}{-96500}=E^0_{cell}$

$-0.121V=E^0_{cell}$

Thus standard cell potential (E∘) for the reaction $X(s)+Y^+(aq)\rightarrow X^+(aq)+Y(s)$ is -0.121 V

5 0

4 years ago

How many L are in 1,500cm^3<br><img src="https://tex.z-dn.net/?f=1500%7Bcm%7D%5E%7B3%7D%20%3D%20%5C%3A%20...%20%20%5C%3A%20liter

irga5000 [103]

1.5 liters are in 1,500cm^3.

8 0

3 years ago

Some fuel cells are powered by hydrogen. Scientists are looking into the decomposition of water (H2O) to make hydrogen fuel with

skad [1K]

A. Decomposing water requires a high activation energy.

Explanation:

In decomposing water to release hydrogen gas to make fuel cells, the process requires a very high activation energy.

2H₂O ⇆ 2H₂ + O₂

This is the overall reaction. O-H must be broken to release free hydrogen to produce hydrogen gas.

The O-H bond is a very strong force of attraction that requires a high activation energy to overcome.

The activation energy is the energy barrier that must be overcome before a reaction takes place.
The sun is a renewable source of energy.
Water decomposition produces useful oxygen gas needed by all life for cellular respiration.

Learn more:

Source of energy brainly.com/question/2948717

#learnwithBrainly

4 0

3 years ago

If a sodium ion (Na+) has a positive charge and loses an electron when combined with chlorine, will the sodium atom become a new

Alina [70]

Answer:

Explanation:

loss of electron doesn't affect the element.

only change in proton number can, as we notice in nuclear chemistry.

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