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stira [4]
4 years ago
8

When water is decomposed into hydrogen and oxygen, these gases cannot combine again to reform water?

Chemistry
1 answer:
Semenov [28]4 years ago
6 0
This statement is false. When water is decomposed into hydrogen and oxygen; these gases are in a position of combining again to reform water. Water is a molecule consisting of one atom of oxygen bound to two hydrogen atoms. The atoms are joined by covalent bonds; however they have addition hydrogen bonds between the partial negative oxygen and the partial positive hydrogen atom.
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Which represents an endothermic reaction? wood burning in a fire splitting a gas molecule changing frost to water vapor TNT expl
scoundrel [369]

Answer:

changing frost into water vapors.

Explanation:

8 0
4 years ago
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How many grams of the molecule glucose C6H12O6 would be required to make 1 L of a 0.5 M solution of the molecule?
soldier1979 [14.2K]

Answer:

90g

Explanation:

We need to find the molar mass of C6H12O6. This is done below:

MM of C6H12O6 = (12x6) + (12x1) + (6x16) = 72 + 12 + 96 = 180g/mol

From the question, we obtained:

Volume = 1L

Molarity = 0.5M

Number of mole = Molarity x Volume

Number of mole = 0.5 x 1 = 0.5mol

Mass conc of C6H12O6 = number of mole x MM = 0.5 x 180 = 90g

6 0
3 years ago
Which is a diatomic molecule?<br><br> A)He<br><br> B)O2<br><br> C)NaCl<br><br> D)CuF2
Alona [7]
B is the correct answer
5 0
3 years ago
2. Which situation best represents conduction?
ikadub [295]

Answer:

c

Explanation:

touching a hot piece of metal. because the energy or the hotness of the pot is touching your hand which is a direct contact.

8 0
3 years ago
Identify the effect of increasing acidity on the solubility of the given compounds Sr(OH)2 S r( O H) Subscript2 ZnS Z n S PbBr2
Dafna1 [17]

Answer:

Solubilities of Sr(OH)_{2},ZnS,Ca_{3}(PO_{4})_{2} and BaCO_{3} increases with increasing acidity

Explanation:

Sr(OH)_{2}\rightleftharpoons Sr^{2+}+2 OH^{-}

Concentration of OH^{-} decreases with increasing acidity. Therefore solubility of Sr(OH)_{2} increases to keep constant solubility product.

ZnS\rightleftharpoons Zn^{2+}+S^{2-}

Concentration of S^{2-} decreases with increasing acidity due to formation of H_{2}S. therefore solubility of ZnS increases to keep constant solubility product

PbBr_{2}\rightleftharpoons Pb^{2+}+2Br^{-}

Increasing acidity have no effect on this above equilibrium. Therefore solubility of PbBr_{2} remains constant.

Ca_{3}(PO_{4})_{2}\rightleftharpoons 3Ca^{2+}+2PO_{4}^{3-}

Concentration of PO_{4}^{3-} decreases with increasing acidity due to formation of H_{3}PO_{4}. Therefore solubility of Ca_{3}(PO_{4})_{2} increases to keep constant solubility product.

NaI\rightleftharpoons Na^{+}+I^{-}

Increasing acidity have no effect on this above equilibrium. Therefore solubility of NaI remains constant.

BaCO_{3}\rightleftharpoons Ba^{2+}+CO_{3}^{2-}

Concentration of CO_{3}^{2-} decreases with increasing acidity due to formation of H_{2}CO_{3}. Therefore solubility of BaCO_{3} increases to keep constant solubility product.

5 0
3 years ago
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