The coordinates of four points on the line are (0,-5), (3,-3), (6,-1) and (9,1)
<h3>How to determine the coordinates?</h3>
The given parameters are given as:
- Slope, m = 2/3
- y-intercept, c = -5
The equation is represented as:
y = mx + c
So, we have:
y = 2/3x -5
When x = 0, we have;
y = 2/3 * 0 -5 = -5
When x = 3, we have;
y = 2/3 * 3 -5 = -3
When x = 6, we have;
y = 2/3 * 6 -5 = -1
When x = 9, we have;
y = 2/3 * 9 -5 = 1
Hence, the coordinates of four points on the line are (0,-5), (3,-3), (6,-1) and (9,1)
Read more about linear equations at:
brainly.com/question/14323743
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Hey Dammy17,
Ok so what we need to do is "plug in" 2oz for x in the equation,
So, 0.6 (2) + 11 =
0.12 + 11= 11.12 oz is the finishing weight.
