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Radda [10]
3 years ago
5

Find the solution set for this equation:

Mathematics
2 answers:
kotegsom [21]3 years ago
8 0
T(t+7)=0

t = 0, t + 7= 0
t= 0, t = -7
xz_007 [3.2K]3 years ago
4 0

Answer:


Step-by-step explanation:

t(t+7)=0

t = 0, t + 7= 0

t= 0, t = -7

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Can you find the volume of this cylinder for me please??
Morgarella [4.7K]

Answer:

37.7 inches

Step-by-step explanation:

V=πr^2h

Is the formula for the volume of a cylinder

^2 is exponent 2

r is the radius (2) and h is the height (3)

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5 0
3 years ago
GEOMETRY<br><br> *image is attached above*
Keith_Richards [23]

Answer:

(-9.5, -4)

Step-by-step explanation:

Given the ratio a:b (a to b) of two segments formed by a point of partition, and the endpoints of the original segment, we can calculate the point of partition using this formula:

( \frac{a }{a + b} (x_{2} - x_{1}) + x_{1}, \frac{a}{a + b} (y_{2} - y_{1})+y_{1}).

Given two endpoints of the original segment

→ (-10, -8) [(x₁, y₁)] and (-8, 8) [(x₂, y₂)]

Along with the ratio of the two partitioned segments

→ 1 to 3 = 1:3 [a:b]

Formed by the point that partitions the original segment to create the two partitioned ones

→ (x?, y?)

We can apply this formula and understand how it was derived to figure out where the point of partition is.

Here is the substitution:

x₁ = -10

y₁ = -8

x₂ = -8

y₂ = 8

a = 1

b = 3

( \frac{a }{a + b} (x_{2} - x_{1}) + x_{1}, \frac{a}{a + b} (y_{2} - y_{1})+y_{1}). →

( \frac{(1) }{(1) + (3)} ((-8) - (-10)) + (-10), \frac{(1)}{(1) + (3)} ((8) - (-8))+ (-8)) →

( \frac{1}{4} ((-8) - (-10)) + (-10), \frac{1}{4}((8) - (-8)) + (-8)) →

( \frac{1}{4} (2) + (-10), \frac{1}{4}(16) + (-8)) →

( (\frac{1}{2}) + (-10), (4) + (-8)) →

( (-\frac{19}{2}), (-4)) →

( -\frac{19}{2}, -4) →

*( -9.5, -4)*

Now the reason why this

6 0
3 years ago
An acrobat is on a platform that is 25 feet in the air. She jumps down in the initial velocity of 4 feet/seconds . Write the qua
Alenkasestr [34]

Answer:

a) h(t) = -16t²+ 4t + 25

b) Therefore it would take her 1.25 seconds to land safely in the net.

Step-by-step explanation:

The equation to be used is given as

h(t) = –gt²+ vt + S(t)

where g = force of gravity and because our question is in feet's = 16

V= Initial velocity

h = height

S = distance

a) The quadratic function for the above question

Using the formula

v = Initial velocity in the question = 4ft/s

S(t) = 25ft in the air

Hence the Quadratic function is

h(t) = –gt²+ vt + S(t)

h(t) = -16t²+ 4t + 25

b) If the safety net is placed 5 feet above the ground, how long will it take her to land safely in the net?

We are to find the time(t)

We can calculate this by using the quadratic function we derived in question (a)

The quadratic function is

h(t) = -16t²+ 4t + 25

Where, the height (h) = 5 feet above the ground

5= -16t² + 4t + 25

-16t² + 4t + 25 -5 = 0

-16t² + 4t + 20 = 0

Using the quadratic equation formula of

x = -b ± √b² -4ac /2a

where the quadratic equation =

ax² + bx + c = 0

a = -16 , b = 4 , c = 20

x = -16 ± √4² - 4×-16×20 / 2×-16

x = -1 or ,1.25

Therefore it would take her 1.25 seconds to land safely in the net

6 0
3 years ago
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