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RoseWind [281]
3 years ago
13

How do you do this ?

Mathematics
1 answer:
salantis [7]3 years ago
5 0
You would need to find the area of which the irrigation would cover:
Area of a circle=pi*r^2
=300^2*pi
=90000pi ft^2
Hope this helps
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A cylindrical well has a radius of 8 feet and a height of 13 feet what is the volume of the well use 3.14 for pie round your ans
vitfil [10]
To find the volume of a cylinder, you use this formula:
V = \pir^{2}h

Plug in your numbers,
V = (3.14 * 8^{2}) * 13

Exponents:
V = (3.14 * 64) * 13

Parentheses:
V = 200.96 * 13

Multiply:
V = 2612.48ft^{2}
8 0
3 years ago
What are the zeros of the polynomial function f(x) = x3 - 2x2 - 24x? (1 point)
vodka [1.7K]

f(x) = x³ - 2x² - 24x

x³ - 2x² - 24x = 0

x(x² - 2x - 24) = 0

x = 0

x² - 2x - 24 = 0

a = 1, b = -2, c = -24

Delta = (-2)² - 4 * 1 * (-24) = 4 + 96 = 100

x = (-(-2) - 10)/(2 * 1) = -8/2 = -4

x = (-(-2) + 10)/(2 * 1) = 12/2 = 6

Answer: 2)

5 0
3 years ago
Which of the following expressions results in 0 when evaluated at x = 4?
Zarrin [17]
(x-10)(x-4) because 4-10=6 then multiply that by 0 from 4-4
8 0
3 years ago
state whether the lines represented by the equations y=1/2x-1 and y+4=-1/2(x-2) are paraller, perdendicular, or neither
Brrunno [24]
The easiest way to tell whether lines are parallel, perpendicular, or neither is when they are written in slope-intercept form or y = mx + b. We will begin by putting both of our equations into this format.

The first equation, y =  \frac{1}{2}x - 1 is already in slope intercept form. The slope is 1/2 and the y-intercept is -1.

The second equation requires rearranging.
y + 4 =  -\frac{1}{2}(x - 2) \\ y + 4 = -\frac{1}{2}x + 1 \\ y = - \frac{1}{2} x- 3
From this equation, we can see that the slope is -1/2 and the y-intercept is -3.

When lines are parallel, they have the same slope. This is not the case with these lines because one has slope of 1/2 and the other has slope of -1/2. Since these are not the same our lines are not parallel.

When lines are perpendicular, the slope of one is the negative reciprocal of the other. That is, if one had slope 2, the other would have slope -1/2. This also is not the case in this problem.

Thus, we conclude that the lines are neither parallel nor perpendicular.
8 0
3 years ago
Is this a right triangle?​
-BARSIC- [3]
Yes it is a right angle
4 0
2 years ago
Read 2 more answers
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