Answer:
![\frac{1}{3a}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3a%7D)
Step-by-step explanation:
Given
× ![\frac{5}{a-3}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7Ba-3%7D)
Cancel the factor (a - 3) on the numerator and denominator
Cancel the 5 and 15 by dividing both by 5, leaving
![\frac{1}{3a}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3a%7D)
Don’t u already have the answer? Someone marked ur grade. Is this a retake?
Answer:
i think its c
sorry if im wrong!
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
Answer:
1/6
Step-by-step explanation:
Given that :
Total surveyed (u) = 120
n(Cane's chicken fingers) = 50
n(Layne's chicken fingers) = 80
n(do not like either) = 10
a)
What is the probability that someone surveyed likes both Raising Cane's and Layne's chicken fingers?
n(Cane's n Layne's) = 20
u = 120
P = required outcome / total possible outcomes
P(Layne's and Cane's chicken) = [n(Cane's n Layne's)/ u]
= 20 / 120
= 1/6