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yawa3891 [41]
2 years ago
8

Can you find the volume of this cylinder for me please??

Mathematics
2 answers:
Margarita [4]2 years ago
7 0

Answer: 37.68

**37.7** rounded

Step-by-step explanation:

V=πr^2h sooo.... Volume= 3.14 × 2^2 × 3

I hope this helps

            ~Princess <3

Morgarella [4.7K]2 years ago
6 0

Answer:

37.7 inches

Step-by-step explanation:

V=πr^2h

Is the formula for the volume of a cylinder

^2 is exponent 2

r is the radius (2) and h is the height (3)

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Shards of clay vessels were put together to reconstruct rim diameters of the original ceramic vessels found at the Wind Mountain
Otrada [13]

Answer:

a) In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)^2}{n-1}} (3)  

The mean calculated for this case is

The sample deviation calculated s=3.46 \approx 3.5

b) 15.8-1.383\frac{3.5}{\sqrt{10}}=14.27    

15.8+1.383\frac{3.5}{\sqrt{10}}=17.33    

So on this case the 80% confidence interval would be given by (14.27;17.33)  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)^2}{n-1}} (3)  

The mean calculated for this case is

The sample deviation calculated s=3.46 \approx 3.5

Part b

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=10-1=9

Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.1,9)".And we see that t_{\alpha/2}=1.383

Now we have everything in order to replace into formula (1):

15.8-1.383\frac{3.5}{\sqrt{10}}=14.27    

15.8+1.383\frac{3.5}{\sqrt{10}}=17.33    

So on this case the 80% confidence interval would be given by (14.27;17.33)    

6 0
3 years ago
Alex scored 10% in his math test if the test was out of 30, what was his score
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Answer:

Yeesh it was a 3

Step-by-step explanation:

10% of 30=.10 x 30

Answer is 3

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I believe it’s c

Step-by-step explanation:

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IS THIS CORRECT!!!????
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So if it has to be simplified, there is only one answer if all of it is positive but it has a solution to do with minus numbers which is -2 (-x-2)
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