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bearhunter [10]
3 years ago
11

Point A is located at (0,4) and point B is located at (-2,-3). Find the x value for the point that is 1/4 the distance from poin

t A to point B
Mathematics
1 answer:
fiasKO [112]3 years ago
8 0
To solve these questions, use this formula: X3= F(X1-X2) Y3= F(Y1-Y2) Where X3 is the X value in the coordinate your solving for, F is the fraction, X1 is the first X and X2 is the second X Plug in your numbers to fit this: X3= 1/4 x (0--2) Y3= 1/4 x (4- -3) By solving you get: (-.5, 1.75)
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PLEASE HELP I DO NOT UNDERSTAND!
alexgriva [62]

Answer:

1. x = -3

2. x = 4/3

3. x = 698/77

Step-by-step explanation:

4+2x=-2

-4       -4

2x= -6

/2     /2

x=-3

You have to get x alone on one side. Search up on yt "How to solve for x on two sides."

3 0
2 years ago
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Directions : Factor each of the following Differences of two squares and write your answer together with solution​
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\huge \boxed{\mathfrak{Question} \downarrow}

Factor each of the following differences of two squares and write your answer together with solution.

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

<h3><u>1. x² - 36</u></h3>

\sf \: x ^ { 2 } - 36

Rewrite \sf\:x^{2}-36 as x^{2}-6^{2}. The difference of squares can be factored using the rule:\sf\: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

\boxed{ \boxed{ \bf\left(x-6\right)\left(x+6\right) }}

__________________

<h3><u>2. 49 - x²</u></h3>

\sf \: 49 - x ^ { 2 }

Rewrite 49-x² as 7²-x². The difference of squares can be factored using the rule: \sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

\sf \: \left(7-x\right)\left(7+x\right)

Reorder the terms.

\boxed{ \boxed{ \bf\left(-x+7\right)\left(x+7\right) }}

__________________

<h3><u>3. 81 - c²</u></h3>

\sf \: 81 - c ^ { 2 }

Rewrite 81-c²as 9²-c². The difference of squares can be factored using the rule: \sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

\sf\left(9-c\right)\left(9+c\right)

Reorder the terms.

\boxed{ \boxed{ \bf\left(-c+9\right)\left(c+9\right) }}

__________________

<h3><u>4</u><u>.</u><u> </u><u>m²</u><u>n</u><u>²</u><u> </u><u>-</u><u> </u><u>1</u></h3>

\sf \: m ^ { 2 } n ^ { 2 } - 1

Rewrite m²n² - 1 as \sf\left(mn\right)^{2}-1^{2}. The difference of squares can be factored using the rule: \sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

\boxed{ \boxed{ \bf\left(mn-1\right)\left(mn+1\right) }}

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I don't under stand what u asked
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