What is one clam that supports global warming

The pupil of an eagle’s eye has a diameter of 6.0 mm. Two field mice are separated by 0.010 m. From a distance of 185 m, the eag

max2010maxim [7]

Answer:

time is 5.973826 sec

Explanation:

Given data

diameter D = 6.0 mm 6× $10^{-3}$ m

separated d = 0.010 m

distance (dis) 185 m

speed s = 16 m/s

wavelength = 550 nm = 550 $10^{-9}$ m

to find out

How much time passes

solution

we know that for resolution we use Rayleigh's Criterion i.e

θ = 1.22 wavelength / diameter = separated / distance 1

we calculate distance 1 by put value wavelength, diameter and separated

distance 1 = diameter × separated / 1.22 wavelength

distance 1 = 6× $10^{-3}$ × 0.010 / 1.22 × 550 × $10^{-9}$

distance 1 = 89.418778

so time will be i.e = distance (dis) - distance 1 / speed

time = ( 185 - 89.418778) / 16

time = 5.973826 sec

time is 5.973826 sec

4 0

2 years ago

Accurate data _____. A)is free from error B)proves a hypothesis C)disproves a hypothesis D)is always precise

maxonik [38]

The correct choice for this problem is (a)

8 0

2 years ago

Read 2 more answers

11. A student lifts a 25 kg mass a vertical distance of 1.6 m in a time of 2.0 seconds.

goldenfox [79]

Answer:

a) 245 N

b) 392 J

c) 196 W

Explanation:

a) Force needed to lift the 25 kg object is the same as the weight of the object:

$Force= m * g = 25kg * 9.8 \frac{m}{s^2} = 245 N$

b) Work is the force exerted times the distance moved:

$Work = F * d = 245N * 1.6 m = 392 Joules = 392 J$

c) The power exerted is the quotient of the work done over the amount of time it took to move the object:

4 0

2 years ago

If a steel cylindrical specimen is stressed nominally to 53 MPa, what stress level exists at the tip of an elliptical surface fl

ElenaW [278]

Answer:

227.9MPa

Explanation:

Length of the flaws is given by

2b = 5.8microns

b = 2.9 × 10⁻⁶m

The relation between the radius of curvature and length and width of the elliptical flaw

$r = \frac{a^2}{b}$

$a = \sqrt{rb}$

Equation for stress at the tip of an elliptical surface flaw

$\sigma _t = \sigma(1 + 2\frac{b}{a} )\\\\\sigma _t = \sigma(1 + 2\frac{b}{\sqrt{rb} })\\\\\sigma _t = \sigma(1 + 2\frac{\sqrt{b} }{\sqrt{r} })\\\\\sigma _t = \sigma(1 + 2\sqrt{\frac{b}{r} })$

$\sigma _t = 53 \times 10^6 (1 + 2\sqrt{\frac{2.9\times10^-^6 }{1065 \times 10^-^9} } \\\\\sigma _t = 227.9 \times 10^6\\\\\sigma _t = 227.9MPa$

4 0

2 years ago

O SIGNIFICADO ESPECÍFICO NA FÍSICA DO TERMO “FORÇA”? E CITE 03(TRÊS) EXEMPLOS;

liq [111]

Answer:

el cero a la izquierda no tiene ningún valor específico LO contrario a LA DERECHa tiene diferentes valores o cantidades

8 0

2 years ago