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Karo-lina-s [1.5K]
3 years ago
13

Am radio signals are broadcast at frequencies between 550 khz and 1600 khz and travel 2.99792 × 108 m/s. what is the shortest am

wavelength? answer in units of m.
Physics
1 answer:
Mrac [35]3 years ago
4 0
Λ = c/f; where λ is the wavelength, c is the velocity (3.0 ×10^8 m/s) and f is the frequency of the wave.
Therefore; λ1 = (2.99792×10^8)/5.5×10^5)
                      =  545.5 m
                   λ2 = (2.99792×10^8)/1.6×10^6
                       = 187.5 m
Therefore; the shortest wavelength is 187.5 m

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tatiyna

Answer:

96 s.

Explanation:

(a)

From the question,

Q = cm(t₂-t₁)................... Equation 1

Where Q = heat required to boil the water, c = specific heat capacity of the water, m = mass of the water, t₂ = final temperature of water, t₁ = initial temperature of water

Note: The boiling point of water = 100 °C

Given: c = 4200 J/kg.°C, t₂ = 100 °C, t₁ = 20 °C

mass of water = density×volume

m = D×v, Where D = 1000 kg/m³, v = 1.00 L = 0.001 m³

Hence, m = 1000×0.001 = 1 kg.

Substitute into equation 1

Q = 4200×1(100-20)

Q = 4200×8

Q = 33600 J.

But,

P = Q/t................... Equation 2

make t  the subject of the equation

t = Q/P................. Equation 3

Where P = power, t = time

From the question,

70 % of the available energy is absorbed by water.

P = 0.7×500 = 350 W.

Substitute into equation 2

t = 33600/350

t = 96 s.

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