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Karo-lina-s [1.5K]
3 years ago
13

Am radio signals are broadcast at frequencies between 550 khz and 1600 khz and travel 2.99792 × 108 m/s. what is the shortest am

wavelength? answer in units of m.
Physics
1 answer:
Mrac [35]3 years ago
4 0
Λ = c/f; where λ is the wavelength, c is the velocity (3.0 ×10^8 m/s) and f is the frequency of the wave.
Therefore; λ1 = (2.99792×10^8)/5.5×10^5)
                      =  545.5 m
                   λ2 = (2.99792×10^8)/1.6×10^6
                       = 187.5 m
Therefore; the shortest wavelength is 187.5 m

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An iron wire has a cross-sectional area equal to 5.00×10⁻⁶ m² . Carry out the following steps to determine the drift speed of th
Doss [256]
  1. In mass, there are 55.85 × 10⁻³ kg/mol in in 1 mole of iron.
  2. The molar density of iron is equal to 1.41 × 10⁵ mol/m³.
  3. The density of iron atoms is equal to 8.49 × 10²⁸ atoms/m³.
  4. The number density of conduction electrons is equal to 1.70 × 10²⁹ conduction electrons/m³.
  5. The drift speed of conduction electrons is equal to 2.21 × 10⁻⁴ m/s.

<h3>How to calculate the drift speed of the conduction electrons?</h3>

Mathematically, the drift speed of the conduction electrons can be calculated by using this formula:

V = (m × σ × V)/ρ × e × f × l)

V = I/(n × A × Q)

Where:

  • U represents the drift speed of the conduction electrons, in m/s.
  • m represents the molecular mass of the metal, in kg.
  • e represents the elementary charge, in C.
  • f represents the number of free electrons per atom.
  • σ represents the electric conductivity of the medium at a particular temperature in S/m.
  • ρ represents the density of the conductor, in kg/m³.
  • ℓ represents the length of the conductor, in m.
  • ΔV represents the voltage applied or potential difference across the conductor in V.

<h3>How many kilograms are there in 1 mole of iron? </h3>

Molar mass of iron = 55.85 g/mol.

In Kilograms, we have:

Mass = 55.85 × 1/1000

Mass = 55.85 × 10⁻³ kg/mol.

For the molar density of iron, we have:

Molar density = density/molar mass

Molar density = 7874/0.056

Molar density = 1.41 × 10⁵ mol/m³.

For the density of iron atoms, we have:

Density of iron atoms = Avogadro's constant × molar density

Density of iron atoms = 6.023 × 10²³ × 1.406 × 10⁵

Density of iron atoms = 8.49 × 10²⁸ atoms/m³.

For the number density of conduction electrons, we have:

Fe ---> Fe²⁺ + 2e⁻

Number density of conduction electrons = 2 conduction electrons/1 atom of iron

Number density of conduction electrons = 2 × 8.49 × 10²⁸

Number density of conduction electrons = 1.70 × 10²⁹ conduction electrons/m³.

For the drift speed of conduction electrons, we have:

V = I/(n × A × Q)

V = 30/(1.70 × 10²⁹ × 1.602 × 10⁻¹⁹ × 5 × 10⁻⁶)

Drift speed, V = 2.21 × 10⁻⁴ m/s.

Read more on drift speed here: brainly.com/question/15219891

#SPJ4

Complete Question:

An iron wire has a cross-sectional area of 5.00 x 10-6 m2. Carry out steps (a) through (e) to compute the drift speed of the conduction electrons in the wire.

(a) How many kilograms are there in 1 mole of iron?

(b) Starting with the density of iron and the result of part (a), compute the molar density of iron (the number of moles of iron per cubic meter).

(c) Calculate the number density of iron atoms using Avogadro’s number.

(d) Obtain the number density of conduction electrons given that there are two conduction electrons per iron atom.

(e) If the wire carries a current of 30.0 A, calculate the drift speed of conduction electrons.

4 0
2 years ago
When a wave has λ=3 m and f=15 Hz, what is the speed of the wave?
Tamiku [17]

Wave speed = (wavelength) x (frequency)

Wave speed = (3 m) x (15 Hz)

<em>Wave speed = 45 m/s</em>

5 0
3 years ago
If we increase the driving frequency in a circuit with purely resistive load, how do the amplitudes VR and IR change?
Lady_Fox [76]

Answer:

V = I R    

expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

Explanation:

In a purely resistive circuit, the Ohm relation, m for which

          V = I R

We see that the previous expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

This does not happen in circuits with capacitors or inductors where there is an explicit dependence on frequency.

3 0
3 years ago
Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that they emit sound w
weeeeeb [17]

Question:

If you are 3.00 m from speaker A directly to your right and 3.50 m from speaker B directly to your left. What is the shortest distance d you need to walk forward to be at a point where you cannot hear the speakers?

Answer:

The shortest distance d you need to walk forward to be at a point where you cannot hear the speakers is 5.625 m

Explanation:

Shortest distance is given by

For constructive interference of wave, we have

\Delta r_{construct} = 2nλ/2

For destructive interference of wave, we have

\Delta r_{destruct} = (2n+1)λ/2

That is the difference in the number of wavelength between constructive and destructive interference is λ/2

We note that our positioning is 3.0 m from the first speaker and 3.5 m from the second, Which is of the form 2n and 2n + 1

Therefore when we walk forward away from the two speakers, we cannot hear the speakers at

Δr = λ/2 = r_B - r_A

Which is the distance between the points where we have constructive and destructive interference or where there is destructive interference between the waves

Where:

r_A =  Distance from  speaker A and

r_B = Distance from  speaker B

λ/2 = (344 m/s /688 Hz)/2

= 1/4

For

λ/2 = r_B - r_A  we have

√(3.5² +d²) - √(3²+d²) = 1/4

∴ d = 5.625 m

6 0
3 years ago
When is your weight is equal to mg?<br>​
Vinil7 [7]

Answer:

The weight of an object is defined as the force of gravity on the object and may be calculated as the mass times the acceleration of gravity, w = mg.

6 0
4 years ago
Read 2 more answers
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