Answer:
The kinetic energy K of a moving object is: K= 1/2mv to the second power
where m is the mass and v the velocity of the object.
Using this formula, we can calculate v for this problem
Explanation:
Answer:
t = 0.354 hours
Explanation:
given,
coefficient of rolling friction μr=0.002
mass of locomotive = 180,000 Kg
rolling speed = 25 m/s
The force of friction = μ mg
= (.002) x (180000) x (9.8)
= 3528 N
F = m a
now,
m a = 3528 N
180000 x a = 3528
a = 0.0196 m/s²
Then apply
v = u + at
0 = 25 - 0.0196 x t
t = 1275.51 sec
t = 1275.61/3600 hours
t = 0.354 hours
time taken by the locomotive to stop = t = 0.354 hours
Answer:
-4.1μC is the final charge on the third sphere
Explanation:
From the given data, q1 and q2 are brought into contact as they are both conductors, as such there will be evenly distribution of charges.
a) charge on each sphere(Q) = q1 + q2 / 2
= +3.8 μC + (- 2.6 μC) / 2 = 1.2μC/2 = 0.6μC
b) Now, one of those two spheres is brought into contact with the third sphere ; Q is brought into contact with q3 = Q + q3 / 2
= 0.6μC - 8.8 μC /2 = -8.2 μC/2
= -4.1μC is the final charge on the third sphere.
