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2 years ago

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A truck of mass 10000kg moving through a sloppy road of length 20km with the help of 5000N force. If the truck climbs the vertic

al height of 200m and it's efficiency is 80% calculate the additional mass that can be carried by the truck ?

1 answer:

gizmo_the_mogwai [7]2 years ago

4 0

Answer:

30000

Explanation:

Statement of the given problem,

A truck of mass 10000 kg is moving through a sloppy road of length 20 km with the help of 5000 N force. If the truck climb the vertical height of 200 m and its efficiency is 80% calculate the additional mass that can be carried by the truck?

Let M denotes the additional mass (in kg) that can be carried by the truck.

From above data we determine that,

P.E. gained by total mass at the vertical height of 200 m = 80% of work done by the applied force [road elevation = tan^-1 (200/20000) = 0.57° (assumed negligible)]

Hence we get following relation,

(10000 + M)*g*200 = 5000*20*1000*80/100 [g = gravitational acceleration]

or 10000 + M = 50000*8/g = 50000*8/10 [g = 10 m/s^2 (assumed)]

or M = 40000 - 10000 = 30000 (kg) [Ans]

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