Answer:
30000
Explanation:
Statement of the given problem,
A truck of mass 10000 kg is moving through a sloppy road of length 20 km with the help of 5000 N force. If the truck climb the vertical height of 200 m and its efficiency is 80% calculate the additional mass that can be carried by the truck?
Let M denotes the additional mass (in kg) that can be carried by the truck.
From above data we determine that,
P.E. gained by total mass at the vertical height of 200 m = 80% of work done by the applied force [road elevation = tan^-1 (200/20000) = 0.57° (assumed negligible)]
Hence we get following relation,
(10000 + M)*g*200 = 5000*20*1000*80/100 [g = gravitational acceleration]
or 10000 + M = 50000*8/g = 50000*8/10 [g = 10 m/s^2 (assumed)]
or M = 40000 - 10000 = 30000 (kg) [Ans]
