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Alex777 [14]
4 years ago
11

If a proton with velocity v is inside a uniform magnetic field, the work done on the proton by the magnetic field is greater tha

n zero. True OR False
Physics
1 answer:
Kipish [7]4 years ago
7 0

Answer:

ZERO

Explanation:

As we know that force due to magnetic field on moving charge is given by

\vec F = q(\vec v \times \vec B)

now here we can say that the force due to magnetic field is always perpendicular to the velocity and it is also perpendicular to the magnetic field.

So we can say that

\vec F. \vec v = 0

so power due to magnetic field is always zero

which shows that rate of work done by magnetic field on moving charge is zero

so here the work done by magnetic field is always zero

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A moving object has a kinetic energy of 150 j and a momentum with a magnitude of 30.0 kg•m/s. determine the mass and speed of th
SOVA2 [1]
To determine the answer to this item, we use two (2) equations.

Equation for kinetic energy:
   KE = 0.5 mv²

Equation for momentum:
  P = mv

From the second equation, we can deduced that,
  m = P/v
Substituting the known values from the given above,

  m = 30/v

Using this expression in the first equation,

  KE = 0.5 mv²;   150 = 0.5(30/v)(v²)

The value of v from the equation is 10 m/s. 

The mass is therefore calculated as such,
  m = 30/v = 30/10 = 3 kg

Hence, the answers are,

<em> Mass  = 3 kg</em>
<em> Velocity = 10 m/s</em>
4 0
3 years ago
A fish maintains its depth in fresh water by adjusting the air content of porous bone or air sacs to make its average density th
Gnom [1K]

Answer:

V’/V= 1.05  

Explanation:

The density is defined with the ratio of the mass to the volume, for the fish with the collapsed sack

         ρ₁ = m / V

The density of the fish with the bag full of air is

         ρ₂ = m / V’

For the fish to float if it exerts its density must be exactly equal to that of the surrounding water

We clear the mass  and match

          m = ρ1 V = ρ2 V'        

          ρ₁ V = ρ₂ V’

         V ’/ V = ​​ρ₁ / ρ₂

         V ’/ V = ​​1.05 / 1

        V ’= 1.05 V

This is that the fish should increase its volume by 5%

8 0
3 years ago
3. The soccer kicker kicks a 2 kg football with a force of 68 N. How fast will the ball accelerate down the field?
Katen [24]

Answer:

\boxed {\boxed {\sf m= 2 \ kg , \\a= 34 \ m/s^2,  \\\F= 68 \ N}}

Explanation:

The formula for force is:

F=m*a

If we rearrange the formula to solve for a (acceleration), the formula becomes

\frac{F}{m} =a

The force is 68 Newtons. Let's convert the units to make the problem easier later on. 1 N is equal to 1 kg*m/s², so the force of 68 N is equal to 68 kg*m/s².

The mass is 2 kilograms.

F=68 \ kg*m/s^2 \\m= 2\ kg

Substitute the values into the formula.

\frac{68 \ kg*m/s^2}{2 \ kg} =a

Divide. Note that the kilograms will cancel each other out (hence why we changed the units).

\frac{68 \ m/s^2}{2}=a

34 \ m/s^2=a

The acceleration is<u> </u><u>34 meters per second squared.</u>

6 0
3 years ago
Two steel balls, of masses m1=1.00 kg and m2=2.00 kg, respectively, are hung from the ceiling with light strings next to each ot
Zolol [24]

Answer:

(a) The maximum height achieved by the first ball, m₁ is 0.11 m

(a) The maximum height achieved by the second ball, m₂ ball is 0.44 m

Explanation:

Given;

mass of the first ball, m₁ = 1 kg

mass of the second ball, m₂ = 2 kg

The velocity of the first when released from a height of 1 m before collision;

u₁² = u₀² + 2gh

u₀ = 0, since it was released from rest

u₁² =  2gh

u₁² = 2 x 9.8 x 1

u₁² = 19.6

u₁ = √19.6

u₁ = 4.427 m/s

The velocity of the second ball before collision, u₂ = 0

Apply the principle of conservation of linear momentum, to determine the velocity of the balls after an elastic collision.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

v₁ is the final velocity of the first ball after an elastic collision

v₂ is the final velocity of the second ball after an elastic collision

m₁u₁ + m₂(0) = m₁v₁ + m₂v₂

m₁u₁ =  m₁v₁ + m₂v₂

1 x 4.427 = v₁ + 2v₂

v₁ + 2v₂ = 4.427

v₁  = 4.427 - 2v₂  ----- equation (1)

one directional velocity;

u₁ + v₁ = u₂ + v₂

u₂ = 0

u₁ + v₁ = v₂

v₁ = v₂ - u₁

v₁ = v₂ - 4.427 ------ equation (2)

Substitute v₁ into equation (1)

v₂ - 4.427 = 4.427 - 2v₂

3v₂ = 4.427 + 4.427

3v₂  = 8.854

v₂ = 8.854 / 3

v₂  = 2.95 m/s (→ forward direction)

v₁ = v₂ - 4.427

v₁ = 2.95 - 4.427

v₁  = - 1.477 m/s

v₁  = 1.477 m/s ( ← backward direction)

Apply the law of conservation of mechanical energy

mgh_{max} = \frac{1}{2}mv_{max}^2

(a) The maximum height achieved by the first ball (v₁  = 1.477 m/s)

mgh_{max} = \frac{1}{2}mv_{max}^2 \\\\gh_{max} = \frac{1}{2}v_{max}^2\\\\ h_{max}  =  \frac{1}{2g}v_{max}^2\\\\ h_{max}  = \frac{1}{2*9.8}(1.477^2)\\\\ h_{max}  = 0.11 \ m

(b) The maximum height achieved by the second ball (v₂  = 2.95 m/s)

mgh_{max} = \frac{1}{2}mv_{max}^2 \\\\gh_{max} = \frac{1}{2}v_{max}^2\\\\ h_{max}  =  \frac{1}{2g}v_{max}^2\\\\ h_{max}  = \frac{1}{2*9.8}(2.95^2)\\\\ h_{max}  = 0.44 \ m

6 0
3 years ago
T/F all compounds are molecules but NOT all molecules are compounds.
Solnce55 [7]
True because molecules don't have to be compounds but compounds have to be molecules
7 0
3 years ago
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