The volume of the tire at the given diameter and thickness of tube is determined as 1,128.2 cubic inch.
<h3>What is volume?</h3>
Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.
<h3>
Volume of the tire</h3>
The volume of the tire is the measure of the product of area and thickness of the tire.
The volume of the tire is calculated as follows;
Radius of the tire = 0.5 x 26" = 13"
Volume of the tire = Area x thickness
Volume of the tire = πr² x h
where;
- r is the radius of the tire
- h is the thickness of the tube
Volume of the tire = π(13)² x (2.125)
Volume of the tire = 1,128.2 cubic inch
Thus, the volume of the tire at the given diameter and thickness of tube is determined as 1,128.2 cubic inch.
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<h2>Answer </h2>
Option C - Carbon Dioxide and Water
<u>Explanation </u>
The chemical equation reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O).
CH4 + 2O2 → CO2 + 2H2O.
In this equation, carbon dioxide and water are products. Products are substances which are formed after a chemical reaction so in this case carbon dioxide and water are formed as a result after a chemical reaction. Therefore, these are products of reaction of methane and oxygen gas.
Answer:
a) T = (2,375 ± 0.008) s
, b) When comparing this interval with the experimental value we see that it is within the possible theoretical values.
Explanation:
a) The period of a simple pendulum is
T = 2π √ L / g
Let's calculate
T = 2π √1.40 / 9.8
T = 2.3748 s
The uncertainty of the period is
ΔT = dT / dL ΔL
ΔT = 2π ½ √g/L 1/g ΔL
ΔT = π/g √g/L ΔL
ΔT = π/9.8 √9.8/1.4 0.01
ΔT = 0.008 s
The result for the period is
T = (2,375 ± 0.008) s
b) the experimental measure was T = 2.39 s ± 0.01 s
The theoretical value is comprised in a range of [2,367, 2,387] when we approximate this measure according to the significant figures the interval remains [2,37, 2,39].
When comparing this interval with the experimental value we see that it is within the possible theoretical values.
Answer:
There would be 9 b/c there is so many hours of school and the homework depends on how old you are so i am pretty sure it is C.
Explanation:
Answer:
a = 1.152s
b = 0.817 m
c = 7.29m/s
Explanation: let the following
From the first equation of linear motion
V = u+at..........1
parameters be represented as :
t = Time taken
v = Final velocity
a = Acceleration due to gravity = 9.8m/s²
u = Initial velocity = 4 m/s
s = Displacement
V = 0
Substitute the values into equation 1
0 = 4-9.8(t)
-4 = -9.8t
t = 4/9.8
t = 0.408s
From : s = ut+1/2at^2.........2
S = 4×0.408+0.5(-9.8)×0.408^2
S= 1.632-4.9(0.166)
S = 1.632-0.815
S = 0.817m
Her highest height above the board is 0.817 m
Total height she would fall is 0.817+1.90 = 2.717 m
From equation 2
s = ut+1/2at^2
2.717 m = 0t+0.5(9.8)t^2
2.717 m = 0+4.9t^2
2.717 m = 4.9t^2
2.717/4.9 = t^2
0.554 =t^2
t =√0.554
t = 0.744s
Hence, her feet were in the air for 0.744+0.408seconds
= 1.152s
Also recall from equation 1
V= u+at
V = 0+9.8(0.744)
V = 7.29m/s
Hence, the velocity when she hits the water is 7.29m/s
Finally,
a = 1.152s
b = 0.817 m
c = 7.29m/s
