Question

Two identical particles each of mass M and charge Q are placed a certain distance apart. If they are in equilibrium

Answer 1

Answer:

 Q / m = 8.61 10⁻¹¹ C / kg

Explanation:

For this exercise we use the gravitational force of attraction

           

     $F_g = G \frac{m_1m_2}{r^2}$

the electric force

     $F_e = k \frac{q1q2}{r^2}$

indicate that the two forces are equal

     G m₁ m₂ / r² = k q₁ q₂ / r²

they also say that the two masses are equal and the two charges are equal

     G m² = k Q²

     Q / m =  $\sqrt{\frac{G}{k} }$

we calculate

      Q / m = $\sqrt{\frac{6.67 \ 10^{-11} }{8.99 \ 10^9} }$

      Q / m = $\sqrt{ 0.7419 \ 10 ^{-20}}$

       Q / m = 0.861 10⁻¹⁰

       Q / m = 8.61 10⁻¹¹ C / kg