Answer:
167.7
Step-by-step explanation:
210cos(37)=167.7134571
just type it in a calculator
The answer is 1/20 .............
Answer: Its factored form will be
![6n(n-1)(n^2-3n-3)](https://tex.z-dn.net/?f=6n%28n-1%29%28n%5E2-3n-3%29)
Step-by-step explanation:
Since we have given that
![6n^4-24n^3+18n](https://tex.z-dn.net/?f=6n%5E4-24n%5E3%2B18n)
So, we need to factor ,
![6n(n^3-4n^2+3)](https://tex.z-dn.net/?f=6n%28n%5E3-4n%5E2%2B3%29)
Now,
![\text{Let }p(n)=n^3-4n^2+3](https://tex.z-dn.net/?f=%5Ctext%7BLet%20%7Dp%28n%29%3Dn%5E3-4n%5E2%2B3)
Now, by hit and trial method, we put n=1,
![p(1)=1^3-4\times1^2+3=1-4+3=1-1=0](https://tex.z-dn.net/?f=p%281%29%3D1%5E3-4%5Ctimes1%5E2%2B3%3D1-4%2B3%3D1-1%3D0)
![n=1\\n-1=0](https://tex.z-dn.net/?f=n%3D1%5C%5Cn-1%3D0)
So, n-1 is also factor of p(n).
Now,
![\frac{n^3-4n^2+3}{n-1}=n^2-3n-3](https://tex.z-dn.net/?f=%5Cfrac%7Bn%5E3-4n%5E2%2B3%7D%7Bn-1%7D%3Dn%5E2-3n-3)
So, its factored form will be
![6n(n-1)(n^2-3n-3)](https://tex.z-dn.net/?f=6n%28n-1%29%28n%5E2-3n-3%29)
The volume of the sawdust pile is 11,039.06 ft³.
<h3>What is the volume of the pile?
</h3>
The shape of the sawdust pile would be a cone. The diameter is always proportional to its height.
Diameter = k x height
where k is equivalent to the rate of increase of the diameter with respect to the increase in height.
25= k20
k = 25 / 20
k = 1.25
Diameter when height is 30 ft = 1.25x 30 = 35.50 feet
Volume of the sawdust =
πr²h
Where:
- π = 3.14
- r = radius = diameter / 2 = 35.50 / 2 = 18.75
- h = 30
x 3.14 x 18.75² x 30 = 11,039.06 ft³
To learn more about the volume of a cone, please check: brainly.com/question/13705125
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Answer:its A. 3/7 because it would be 12:28 so you'd simplify it.
Step-by-step explanation:
12/28=3/7