-2 = - x + x^2 -4 => x^2 - x - 4 + 2 = 0
x^2 - x - 2 = 0
a is the coefficient of x^2 => a = 1
b is the coefficient of x => b = - 1
c is the constant term => c = - 2
quadratic equation: [- b +/- √(b^2 - 4ac) ] / 2a =
= { 1 +/- √[ (-1)^2 - 4(1)(-2)] } / (2(1) = { 1 +/- √ (1 + 8) } / 2 = {1 +/- √9} / 2 =
= { 1 +/- 3} / 2
No, the 2 lines can never ever be both parallel and perpendicular if I'm not mistaken. This is because a set of parallel lines will never touch each other at all. However perpendicular lines are two lines that meet up to get an angle of 90. You cannot have two lines that never touch and touch at the same time.
Answer:
R = -8 1/6
Step-by-step explanation:
We'll solve the given equation for R.
Subtract 3 1/2 from both sides of the equation, to isolate R:
R + 3 1/2 - 3 1/2 = -4 2/3 - 3 1/2, or
R = -4 2/3 - 3 1/2
The LCD here is 6, which is the product of 3 and 2. Converting the fractions to denominator 6, we get:
R = -4 4/6 - 3 3/6, or
R = -7 - 7/6, or R = -7 - 1 1/6, or -8 1/6
plane 1 travels 395 miles in 1 hour
plane 2 travels 422 miles in 1 hour
together, they travel (395+422) 817 miles in 1 hour
to have 2451 miles between then, they'd need to travel

so in 3 hours, they'll be 2451 miles apart