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slega [8]
3 years ago
14

Question 15

Chemistry
2 answers:
Rina8888 [55]3 years ago
6 0

Answer:

1.184 g

Explanation:

Natalka [10]3 years ago
3 0
Lmk if u need anything to be explained

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For test 6 (150 hevy 50 light particles), what is the pressure contribution from the heavy particles?
lawyer [7]

Answer:

The pressure contribution from the heavy particles is 17.5 atm

Explanation:

According to Dalton's law of partial pressures, if there is a mixture of gases which do not react chemically together, then the total pressure exerted by the mixture is the sum of the partial pressures of the individual gases that make up the mixture.

In the simulation:

the pressure of the 50 light particles alone was determined to be 5.9 atm, the pressure of the 150 heavy particles alone was measured to be 17.5 atm,

the total pressure of the mixture of 150 heavy and 50 light particles was measured to be 23.4 atm

Total pressure = partial pressure of Heavy particles + partial pressure of light particles

23.4 atm = partial pressure of Heavy particles + 5.9 atm

Partial pressure of Heavy particles = (23.4 - 5.9) atm

Partial pressure of Heavy particles = 17.5 atm

Therefore, the pressure contribution from the heavy particles is 17.5 atm

4 0
3 years ago
Can I please Get Help with This Question ‍♂️?
Stolb23 [73]

Answer:

621.41 grams

Explanation:

First of all, to find the mass. You have to use the molar mass of AlBr3 to convert from moles to mass.

Second of all, find the molar mass of AlBr3.

Al = 27.0 amu

Br = 79.9 amu

They are 3 bromine atoms and 1 aluminum atom.

So you do this

27.0 + 79.9(3) = 266.7

The molar mass is 266.7 g/mol

Third of all, use dimensional analysis to show your work.

2.33 moles of AlBr3 * 266.7 g/mol / 1 mol

Moles cancel out.

2.33 x 266.7 = 621.411

Your teacher though said to round digits after the decimal point instead of using sig figs.

621.411 rounds to 621.41

So the final answer is 621.41 grams(don't forger the units).

The substance formula is just AlBr3.

That's all.

Hope it helped!

8 0
3 years ago
How will the changes listed affect the position of the following equilibrium? 2 NO2(g) 4 NO(g) 1 NO3(g) a. The concentration of
grandymaker [24]

Answer:

(a) backward direction

(b) forward direction

(c) no change

Explanation:

(a)

On increasing the concentration of NO , the reaction will go in backward direction , as, according to le chatelier's principle ,

In a chemical equilibrium , when the concentration , pressure or temperature is changed , the equilibrium of the reaction is disturbed , hence, in order to gain attain the equilibrium the reaction moves in order to counteract the changes.

So, in this case, the reaction goes back , to reduce the increased concentration of NO.

(b)

On increasing the concentration of NO2 , the reaction goes in forward direction ,

according to le chatelier's principle ,

the reaction moves in forward direction , to reduce the increased concentration of NO2.

(c)

No change ,

As, changing the volume , does not effect change in the concentration,

Hence,

No change , as the system is allowed to expand to 5 times its initial value.

3 0
4 years ago
A chemist can determine the mass of K in a sample of known mass that consists of either pure K2O or pure K2O2. From this informa
Arte-miy333 [17]

Yes , the chemist can answer if the compound in K2O or K2O2

The chemical formula and composition of both the compounds is entirely different. The compound K2O2 has an additional molecule of oxygen than K2O and hence will have have higher molecular mass.

In the compound K2O

molecular mass= 2x 39+16 =94

mass ratio of K in compound= 78/94 = 0.830

In the compound K2O2

molecular mass= 2x 39+16X2 =110

mass ratio of K in compound= 78/110 = 0.710

and hence by the required ratio while extracting K , the chemist may know if the compound is K20 or K2O2

If the ratio is anything different from 0.830 and 0.710 then the compund will be something different

#SPJ9

5 0
2 years ago
Giving 25 points for this one, need help.
user100 [1]

Answer:

E

Explanation:

3 0
4 years ago
Read 2 more answers
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