Vapour pressure is the pressure exerted by vapour molecules over a liquid surface.
The vapour pressure is a property
a) inter molecular forces: higher the inter molecular forces lower the vapour pressure, In this case we have taken same liquid (milk) hence in all case the inter molecular forces will be same.
b) Temperature: higher the temperature higher the kinetic energy of molecules and more the tendency of liquid molecules to convert to vapor phase.
The vapor pressure will be independent of the container being closes or open.
Thus vapor pressure will be high in Bowl B which is uncovered, and the milk is warmer than room temperature, as it has higher temperature than all other bowl of milk.
Answer:
The answer to your question is MgSO₄ 5H₂O
Explanation:
Data
mass of MgSO₄ = 2.86 g
mass of H₂O = 2.14 g (5 - 2.86)
Process
1.- Calculate the molecular mass of the compounds
MgSO₄ = 24 + 32 + (16 x 4) = 120
H₂O = 16 + 2 = 18
2.- Convert the grams obtain to moles
120 g of MgSO₄ --------------- 1 mol
2.8 g ---------------- x
x = (2.8 x 1)/120
x = 0.024 moles
18 g of H₂O --------------------- 1 mol
2.14 g -------------------- x
x = (2.14 x 1)/18
x = 0.119
3.- Divide by the lowest number of moles
MgSO₄ = 0.024/0.024 = 1
H₂O = 0.119/ 0.024 = 5
4.- Write the molecular formula
MgSO₄5H₂O
option of d is the write answer
Answer:
The balanced chemical equation is given as:
Explanation:
When magnesium metal burns in presence of oxygen it gives white color powdered compound called magnesium oxide.
The balanced chemical equation is given as:
According to reaction, 2 moles of magnesium metal when reacts with 1 mole of oxygen gas it gives 2 moles of solid magnesium oxide.
I think the answer is A. Hope that helped :)
