Your task is to measure the amount of energy evolved during the combustion of some hydrocarbon, then the ideal technique for this experiment would be : Bomb calorimetry
<h3>What is bomb calorimetry?</h3>
Hydrocarbons are combustibles means that they can react in a combustion reaction to produce energy. To measure this energy, it's a necessary equipment so that the reaction can be placed in a controlled way.
The bomb calorimeter is the equipment, which is an adiabatic vessel, with water and heat is calculated based on the increase in the temperature of the water.
Coffee-cup calorimetry is used to measure the heat of a dissolution reaction and bomb manometry is used to measure the pressure.
To know more about bomb calorimetry, refer
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Answer:
Hey!
Your answer is C!
Explanation:
This is because the crust in relation to the Mantle and Core is VERY SMALL (it is in real life)...
The Mantle is about 84% of the Earth's volume and it is represented on the model...
HOPE THIS HELPS!!
4 mutations occured, as four letter we're different 25 million years later. Over one hundred years we can expect it to mutate at the sane rate, but 4 times longer. 4 time 4 is 16 mutations over 100 million years
Let's apply the principle of conservation of energy.
Heat of metal = Heat of water
mCmetalΔT = mCwaterΔT
Applying the given values,
(45 g)(Cmetal)(100 - 28 °C) = (130 g)(4.18 J/g-°C)(28 - 25 °C)
Solving for Cmetal,
<em>Cmetal = 0.503 J/g°C
Therefore, the heat capacity of the unknown metal is 0.503 J/g</em>°C.
Answer:
Explanation:
The half reactions are:
Mg → Mg²⁺ + 2e⁻
2H⁺ + 2e⁻ → H₂
The first equation is an oxidation half while the second is a reduction half. To get the overall reaction equation, we simply combine the two equations. The reactants combines at the left hand side with the products comes together at the right hand side.
Mg + 2H⁺ + 2e⁻ → Mg²⁺ + 2e⁻ + H₂
Now we cancel out the species that appear on both sides:
Mg + 2H⁺ → Mg²⁺ + H₂