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Charra [1.4K]
3 years ago
6

Nevaeh rolls a standard six-sided die, numbered from 1 to 6. Which word or phrase

Mathematics
1 answer:
liubo4ka [24]3 years ago
7 0

Answer:

Step-by-step explanation:

If she had two dice, a seven is the most common roll you can get, although the odds are still against you.

To get a seven with just 1 die is impossible.

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The answer is c:
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Solve Bx+q=A <br> solve for x
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Download Photomath, it gives you the answer for this equations
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3 years ago
Archaeologists can determine the diets of ancient civilizations by measuring the ratio of carbon-13 to carbon-12 in bones found
Vsevolod [243]

Answer:

Step-by-step explanation:

The null and the alternative hypothesis are:

H₀=μ₀=μ₁=μ₂=μ₃=μ₄

H₁=two or more μ are different X

Let X_{ij} denote the jth observation of the ith sample. The mean and the variance of the ith sample is given by

Xbar_{i} =\frac{1}{J_{i}} summation(X_{ij}) where J=1 to J_{i} and  J_{i}  is ith sample size

s_{i} ^{2} =\frac{1}{J_{i}-1 }summation (X_{ij} -   Xbar_{i})^{2}

The sample sizes are J₁ =12   J₂=10   J₃=18   J₄=9

the total number in all samples combined is  49

finding Xbar₁ and s₁

Xbar₁= 1÷12(17.2+....+13.4)

Xbar₁= 17.0500

s₁²= 1÷(12-1) [(17.0500-17.2)+...+(17.0500-13.4)]

s₁²=5.1336

Similarly find the means and variances of other samples

\left[\begin{array}{ccc}i&Mean&variance\\1&17.0500&5.1336\\2&15.4500&13.2317\\3&16.4972&6.9460\\4&15.4444&7.4428\end{array}\right]

the sample grand mean denoted by Xbar is the average of all sampled items taken together:

Xbar=\frac{1}{49} (17.2+.....+16.7)

Xbar=16.2255

Compute the treatment sum of squares SSTr, the sum of squares SSE and the total sum of squares SST

SSTr = ∑ J_{i} (Xbar_{i} -Xbar)^{2}  from i=1 to 49

SSTr= 20.9910

SSE= \sum\limits^I_{i=1}\sum\limits^{J_i}_{j=1}(Xbar_{ij}-Xbar_i)^{2}

SSE=\sum\limits^I_{i=1}(J_i-1)s_i^{2}

SSE=(12-1)(5.1336)+...(9-1)(7.4428)

SSE=353.1796

SST=SSTr+SSE

SST=374.1706

Find the treatment mean square MSTr and the error mean square MSE:

MSTr= SSTr/(I-1)

MSTr=6.9970

MSE=SSE/(N-I)

MSE=7.8484

F=\frac{MSTr}{MSE}

F=0.89

The degrees of freedom are I-1=3 for the numerator and N-I=45 for the denominator. Under H₀, F has an F_{3,45} distribution. To find the P value we consult the F table.

P>0.100

The complete ANOVA table is below

\left[\begin{array}{cccccc}source&DF&SS&MS&F&P\\Agegroup&3&20.9910&6.9970&0.89&0.453\\Error&45&353.1796&7.8484\\Total&48&374.1706\end{array}\right]

(b) The P-value is large. A follower of 5% rule would not reject H₀. Therefore, we cannot conclude the concentration ratios differ among the age groups

4 0
4 years ago
The volume of the barrel is 4.6³ m. It is half water. How many liters of water are there?​
damaskus [11]

Answer:

6.8

Step-by-step explanation:

ggcsefhvse5gvcxdjk bcfhjbhhhhhhhhhiiijvzsd

6 0
3 years ago
If 5 pieces of steel bar each 6 1/2" long are welded together, how long will the new<br> bar be?
sladkih [1.3K]
The new car will be 32.5” long.
6.5 x 5= 32.5
8 0
2 years ago
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