Get a pull chord light switch installed in her bathroom by a qualified electrician asap. Meanwhile, keep hands as dry as possible, and try not to go near that switch until it's either been properly earthed, or whatever the problem actually is, and get qualified advice on what the problem is. Don't have wet feet either, and don't stand in puddles of water whilst operating - i she has to - the switch. 250V AC mains can be lethal, and at least painful.
Answer:
30.5 x 10³ min.
Explanation:
Atomic weight of aluminium = 27
For the reaction
Al⁺³ + 3e = Al
3 mole of electron is required by 1 mole of aluminium
3 x 96500 C of charge is required for 27 gram of aluminium
60.2 g aluminium will require
645.47 x 10³ C
So charge required = 645.47 x 10³ C
Now Charge = Current x time
Current ( given ) = 0.352A
Time = charge / current = 645.47 x 10³ / .352
=1833 x 10³ s
30.5 x 10³ minutes
Answer:
i. 7.5 m
ii. 15000 N
Explanation:
Area under vt graph shows the displacement
so area of triangle ABE= 1/2×15×2
=7.5 m
ii) F=ma
here, m=1000kg
and a=v-u/t
=15-0/1
a=15
F=1000×15=15000N
Answer:
= 5.74W
=0.27 W
Explanation:
d= 2.6cm =>0.026m (for both the ceramic and the carpet )
Thermal conductivity of wool '
'= 
= 
= 0.04J/(sm °C)
Thermal conducticity of carpet '
' = 0.84 J/(sm °C)
Area 'A'= 
= 
= 77.2cm²=> 77.2 x 
m²
=33.0°C
=10.0°C
Average Power 
is determined by dividing amount of energy'Q' by time taken for the transfer't':
= Q/Δt
Due to conductivity, heat of flow rate will be P= dQ/dt
P=
= ![\frac{kA[T_{h}-T_{c} ]}{d}](https://tex.z-dn.net/?f=%5Cfrac%7BkA%5BT_%7Bh%7D-T_%7Bc%7D%20%5D%7D%7Bd%7D)
For CERAMIC:
=![\frac{k_{c} A[T_{h}-T_{c} ]}{d}](https://tex.z-dn.net/?f=%5Cfrac%7Bk_%7Bc%7D%20A%5BT_%7Bh%7D-T_%7Bc%7D%20%5D%7D%7Bd%7D)
=> [0.84 x 77.2 x (33-10) ]/0.026
= 5.74W
For WOOL CARPET:
= ![\frac{k_{w} A[T_{h}-T_{c} ]}{d}](https://tex.z-dn.net/?f=%5Cfrac%7Bk_%7Bw%7D%20A%5BT_%7Bh%7D-T_%7Bc%7D%20%5D%7D%7Bd%7D)
=> [0.04 x 77.2 x (33-10) ]/0.026
=0.27 W
Answer:
B = 0.0307 T = 30.74 mT
Explanation:
Given
m = 0.150 kg
I = 15.0 A
d = 0.510 m
μk = 0.16
B = ?
Balancing the forces on the rod in the <em>j</em> direction
N - m*g = 0 ⇒ N = m*g
and in the <em>i</em> direction
I*d*B - μk*N = 0 ⇒ B = μk*N / (I*d)
⇒ B = μk*m*g / (I*d)
⇒ B = (0.16)*(0.150 kg)*(9.8 m/s²) / (15.0 A*0.510 m)
⇒ B = 0.0307 T = 30.74 mT
