Okay so here's the approach I took:
The potential difference in each of the circuits must be the same so if we derive equations for both the potential differences we can set them equal to each other and solve for R1:
In the first circuit
V = 2.2(R1)
In the second we have to find the equivalent resistor, since they are connected in series:
1/R1 + 1/R2 + 1/R3... = Rt
We have R2 so...
1/R1 + 1/3.1 = Rt
1/R1 + 0.323 = Rt
So...
V = 1.4(1/R1 + 0.323)
Set those equal:
2.2R1 = 1.4(1/R1 + 0.323)
2.2R1 = 1.4(1/R1) + 0.4522
Now multiply everything by R1 so we can combine like terms:
2.2R1^2 = 1.4 + 0.4522R1
Isolate to form a quadratic
2.2R1^2 - 0.4522R1 - 1.4 = 0
Solving this quadratic:
R1 = 0.90708 or R1 = -0.701
Since R cannot be negative
R1 = 0.907 ohms
Answer:
B. Titanium alloy rod
Explanation:
Attached is the full solution
Answer:
the rates of rock formation are similar. i could be wrong tho.....
Explanation:
Answer:
1.12μC
Explanation:
From the expression use to determine the capacitance of a capacitor, which is given below
![C=q/v.........1\\C=E_{0}A/d-----2](https://tex.z-dn.net/?f=C%3Dq%2Fv.........1%5C%5CC%3DE_%7B0%7DA%2Fd-----2)
from the above since the distance,"d" is given is 1.1mm(0.0011m)
Area= 0.3m*0.08=0.024m
V=5.8KV
if we compare both equations above, we can do away with the capacitance
![\frac{q}{v}=\frac{E_{0}A}{d} \\q=\frac{E_{0}Av}{d}\\](https://tex.z-dn.net/?f=%5Cfrac%7Bq%7D%7Bv%7D%3D%5Cfrac%7BE_%7B0%7DA%7D%7Bd%7D%20%20%5C%5Cq%3D%5Cfrac%7BE_%7B0%7DAv%7D%7Bd%7D%5C%5C)
if we substitute the value of the voltage, area, distance and the constant we arrive at
![\\q=\frac{E_{0}Av}{d}\\ q=\frac{8.854*10^{-12}*5800*0.024}{0.0011}\\q=1.12*10^{-6}C\\](https://tex.z-dn.net/?f=%5C%5Cq%3D%5Cfrac%7BE_%7B0%7DAv%7D%7Bd%7D%5C%5C%20q%3D%5Cfrac%7B8.854%2A10%5E%7B-12%7D%2A5800%2A0.024%7D%7B0.0011%7D%5C%5Cq%3D1.12%2A10%5E%7B-6%7DC%5C%5C)
Hence the magnitude of the charge is 1.12μC
The sign associated with the average velocity of the object is negative.
<h3>
Average velocity of the object</h3>
The average velocity of the object is calculated as follows;
Average velocity = (v1 + v2)/2
v1 = -20/30 = -0.667 m/s
v2 = 20/50 = 0.4 m/s
Average velocity = (-0.667 + 0.4)/2
Average velocity = -0.134 m/s
Thus, the sign associated with the average velocity of the object is negative.
Learn more about average velocity here: brainly.com/question/6504879
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