An industrial firm has two electrical loads connected in parallel across the power source. Power is supplied to the firm at 4000
1 answer:
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Answer:
Please refer to the figure.
Explanation:
The crucial point here is to calculate the enclosed current. If the current I is flowing through the whole cross-sectional area of the wire, the current density is
The current density is constant for different parts of the wire. This idea is similar to that of the density of a glass of water is equal to the density of a whole bucket of water.
So,
This enclosed current is now to be used in Ampere’s Law.
Here, represents the circular path of radius r. So we can replace the integral with the circumference of the path,
.
As a result, the magnetic field is
Answer:
60 Ohms
Explanation:
Ohms law states that the voltage in the circuit is directly proportional to the current through the circuit components and expressed as
V=IR
Where V is the voltage, I is current and R is resistance
Making R the subject of the formula then
Substituting 3.0V for V and 0.05 A for I then
Therefore, resistance is 60.0 Ohms
Answer:
book speed is 3.99 m/s
Explanation:
given data
mass m = 490 g = 0.490 kg
compressing x = 7.10 cm = 0.0710 m
spring constant k = 1550 N/m
to find out
book speed
solution
we know energy is conserve so
we can say
loss in spring energy is equal to gain in kinetic energy
so
..................1
put here value
v = 3.99 m/s
so book speed is 3.99 m/s