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Rasek [7]
3 years ago
8

Myopia is a condition of the eye where the crystalline lens focuses the light rays to a position between the lens and the retina

. To correct for this condition, a thin lens is placed in front of the eye that will help to focus light on the retina. The type of lens required is:
Physics
1 answer:
aliya0001 [1]3 years ago
4 0

Answer: concave lens

Explanation:

Myopia is a condition of the eye where someone can only see near distant object clearly but not far distant object.

Myopia is corrected using concave lens (diverging) in order to diverge the rays entering the eye thereby allowing the rays to be focused properly on the retina.

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An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi
Brrunno [24]

Answer:

The explorer should travel to reach base camp to 5.02 Km at 4.28° south of due west.

Explanation:

Using trigonometric function like Sen(Ф), Cos(Ф) and Tan(Ф) we can get distance and direction that the explorer should travel to reach base camp. When we discompound the vector X = 7.8*Cos(50) = 5.01 Km y y = 7.8 * Sen (50) - 5.6 = 5.975 - 5.6 (Km) = 0.375 (Km) so that Tan (\alpha ) = \frac{0.375}{5.01} = 4.28; \alpha = Arctang (\frac{0.375}{5.01}) = 4.28 (degree) to get how far we use Pythagorean theorem so R^{2} = x^{2}+y^{2} so that R=\sqrt{0.375^{2}+5.01^{2} } =5.02 (Km)

6 0
3 years ago
Read 2 more answers
A dentist uses a concave mirror (focal length 2.5 cm) to examine some teeth. If the distance from the object to the mirror is 1.
AysviL [449]

Answer:

2.28

Explanation:

From mirror formula,

1/f = 1/u+1/v .......... Equation 1

Where f = focal length of the mirror, v = image distance, u = object distance.

Note: The focal length mirror is positive.

make v the subject of the equation,

v = fu/(u-f)............ Equation 2

Given: f = 2.5 cm, u = 1.4 cm

Substitute into equation 2

v = 2.5(1.4)/(1.4-2.5)

v = 3.5/-1.1

v = -3.2 cm.

Note: v is negative because it is a virtual image.

But,

Magnification = image distance/object distance

M = v/u

Where M = magnification.

Given: v = 3.2 cm, u = 1.4 cm

M = 3.2/1.4

M = 2.28.

Thus the magnification of the tooth = 2.28.

3 0
3 years ago
Unlike acceleration and velocity, speed does not need to specify
frosja888 [35]

Unlike acceleration and velocity, speed does not need to specify the direction of motion. Speed is a scalar quality.

4 0
3 years ago
I need help with #24 ASAP .. I have to get it done today.. I need help with #24 right now
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Answer:

Explanation: the  temperature range is at 1,400

8 0
2 years ago
An object dropped from rest from the top of a tall building on planet x falls a distance d(t)18 left parenthesis t right parenth
melamori03 [73]

displacement is given by equation

d = 18t^2

now at t = 5 s the position is

d_1 = 18 *5^2 = 450 m

similarly position at t = 9 s

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so the displacement of object in given interval of time will be

d = 1458 - 450 = 1008 m

time interval

\delta t = 9 - 5 = 4 s

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v = \frac{\delta x}{\delta t}

v = \frac{1008}{4} = 252 m/s

so its average speed is 252 m/s

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3 years ago
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