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Len [333]
3 years ago
7

How do you do this question?

Physics
1 answer:
Arte-miy333 [17]3 years ago
5 0

Explanation:

The box has no acceleration in the perpendicular direction, so the net force in that direction is 0.

Sum of forces in the parallel direction:

∑F = f − F∥ − mg∥

∑F = f − F cos φ − mg sin θ

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You are driving on a rural road and see a person on the shoulder ahead, riding or leading an
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How do you get DC current and AC current? from a generator?
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Answer:

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Which of the following is not an example of work?
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8 0
3 years ago
Four uniform spheres, with masses mA = 200 kg, mB = 250 kg, mC = 1700 kg, and mD = 100 kg, have (x, y) coordinates of (0, 50 cm)
rusak2 [61]

Answer:

F_2=2.43\times10^{-19}\ N

\theta=21.496^{\circ} in the anticlockwise direction from the positive x- axis.

Explanation:

Given are the masses of various spheres with their names in subscript:

  • m_A=200\ kg
  • m_B=250\ kg
  • m_C=1700\ kg
  • m_D=100\ kg

Now their respective coordinate positions (in cm) are as given below:

  • P_A=(0,50)
  • P_B=(0,0)
  • P_C=(-80,0)
  • P_D=(40,0)

<u>Now force on B due to A:</u>

F_{BA}=G\times \frac{200\times 250}{50^2}

F_{BA}=20G\ N

<u>Now force on B due to C:</u>

F_{BC}=G\times \frac{1700\times 250}{80^2}

F_{BC}=66.406G\ N

<u>Now force on B due to D:</u>

F_{BD}=G\times \frac{100\times 250}{40^2}

F_{BD}=15.625G\ N

<em>We observe that the forces due to masses  C&D act opposite in direction.</em>

<u>So, the net force in the x-direction:</u>

F_x=F_{BC}-F_{BD}

F_x=66.406G-15.625G

F_x=50.781G\ N in the positive x-direction

<em>We have only one force in y-direction due to mass A.</em>

So,

F_y=20G\ N in the positive y-direction.

<u>Now the net force:</u>

F_2=\sqrt{F_y^2+F_x^2}

F_2=\sqrt{(20G)^2+(50.781G)^2}

F_2=54.5776G^2\ N

F_2=2.43\times10^{-19}\ N

<u>Now the direction of this force with respect to x-axis:</u>

tan\ \theta=\frac{F_y}{F_x}

tan\ \theta=\frac{20G}{50.781G}

\theta=21.496^{\circ} in the anticlockwise direction from the positive x- axis.

3 0
3 years ago
Read 2 more answers
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