Answer:
.5(3120kg)(22.1m/s)^2 = 7.62x10^5 J
Explanation:
Answer:
21.21 m/s
Explanation:
Let KE₁ represent the initial kinetic energy.
Let v₁ represent the initial velocity.
Let KE₂ represent the final kinetic energy.
Let v₂ represent the final velocity.
Next, the data obtained from the question:
Initial velocity (v₁) = 15 m/s
Initial kinetic Energy (KE₁) = E
Final final energy (KE₂) = double the initial kinetic energy = 2E
Final velocity (v₂) =?
Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:
KE = ½mv²
NOTE: Mass (m) = constant (since we are considering the same car)
KE₁/v₁² = KE₂/v₂²
E /15² = 2E/v₂²
E/225 = 2E/v₂²
Cross multiply
E × v₂² = 225 × 2E
E × v₂² = 450E
Divide both side by E
v₂² = 450E /E
v₂² = 450
Take the square root of both side.
v₂ = √450
v₂ = 21.21 m/s
Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.
Answer:
a) Image attached
b) It is acting CW
c) τ = 0.294N.m
Explanation:
As you can see in the image, the ruler will rotate clockwise.
For the total torque: τ = -W*(0.5 - 0.35) The distance used is from 35cm to 50cm
τ = -0.294N.m The magnitude is therefore: 0.294N
Answer:
There always is an acceleration in a curvilinear motion, as the velocity vector changes, so always.
