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hichkok12 [17]
1 year ago
12

What is the porosity of the gravel sample?(The sediment volume for each sample is 400ml. ) a. 23. 75% b. 28. 75% c. 55. 75% d. 8

1. 75%.
Mathematics
1 answer:
Anna [14]1 year ago
4 0

The porosity of the gravel sample is 28.75%

We have to determine.

What is the porosity of the gravel sample?

<h3>The porosity of the gravel sample;</h3>

Porosity is the term which is defined as the volume of voids present in the soil to the total volume of the soil.

The formula used to calculate the Porosity is;

\rm Porosity =\dfrac{Volume \ of \ voids \ present \ in soil}{Volume \ of \ soil}

A sponge is a case of a permeable fabric because it incorporates a huge number of purge spaces compared to its volume.

Porosity is the property of a question that communicates the entire volume of purge or pore space within the material.

Hence, the porosity of the gravel sample is 28.75%

Learn more about "porosity" :

brainly.com/question/2593663

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Step-by-step explanation:

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An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
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Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

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Point M (-3, 5) is translated using this rule. (x, y) ----&gt; (x - 1, y) What are the coordinates of M'?
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Answer:

The coordinates of point M' are M'(x,y) = (-4, 5).

Step-by-step explanation:

According to the statement, we have the following translation rule:

M'(x,y) = M(x,y) + (-1, 0) (1)

Where:

M(x,y) - Original point.

M'(x,y) - Translated point.

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If we know that M(x,y) = (-3, 5), then the coordinates of the point M' are:

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The coordinates of point M' are M'(x,y) = (-4, 5).

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Step-by-step explanation:

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