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sergiy2304 [10]
3 years ago
14

What’s the class width

Mathematics
1 answer:
aksik [14]3 years ago
6 0

Answer:

4

Step-by-step explanation:

Class width is said to be the difference between the upper class limit and the lower class limit consecutive classes of a grouped data. To calculate class width, this formula can be used:

CW = UCL - LCL

Where,

CW= Class width

UCL= Upper class limit

LCL= Lower class limit

From the table above:

For class 1, CW = 64 - 60 = 4

For class 2, CW = 69 - 65 = 4

For class 3, CW = 74 - 70 = 4

For class 4, CW = 79 - 75 = 4

For class 5, CW = 84 - 80 = 4

Therefore, the class width of the grouped data = 4

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A=1/2h(a+b), solve for a
telo118 [61]

Step-by-step explanation:

2A=h(a+b)

2A=ha+hb

2A-hb=ha

2A-hb/h=a

4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=4x%20%7B%7D%5E%7B2%7D%20%20%2B%2020x%20%2B%2025" id="TexFormula1" title="4x {}^{2} + 20x + 25
BigorU [14]

\sf{\qquad\qquad\huge\underline{{\sf Answer}}}

Let's Solve ~

\qquad \sf  \dashrightarrow \: 4 {x}^{2}  + 20x + 25

\qquad \sf  \dashrightarrow \: 4 {x}^{2}  + 10x + 10x + 25

\qquad \sf  \dashrightarrow \: 2x(2x + 5) + 5(2x + 5)

\qquad \sf  \dashrightarrow \: (2x + 5) (2x + 5)

\qquad \sf  \dashrightarrow \: (2x + 5) {}^{2}

or

\sf{\qquad \sf  \dashrightarrow \: 4x² + 20x + 25 }

\sf{\qquad \sf  \dashrightarrow \: (2x)² + (2 \sdot 2x \sdot 5) + (5)²}

[ it's similar to expression - a² + 2ab + b² that is equal to (a + b)² ]

so, let's use this identity here to factorise :

\sf{\qquad \sf  \dashrightarrow \: (2x + 5)²}

I hope it was helpful ~

3 0
2 years ago
What would be the appropriate units and intervals to use along the x- and y-axes
Vika [28.1K]

X axes are supposed to be positive and the y is negative.

3 0
3 years ago
If several students from a middle school stood in a circle evenly spaced to play a game if the 6th student was directly across f
IRINA_888 [86]

Answer:

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Step-by-step explanation:

Its like a clock, except directly away from the six is not twelve, it's 13. That means the clock would have to have added two numbers for there to be a whole number facing the six.

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3 years ago
Can someone pleas answer this
Dima020 [189]

83.7 m

18.6 / 3.6 = 5.166667

16.2*5.166667 = 83.7 m

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