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ArbitrLikvidat [17]
4 years ago
14

What is the equation of (4,10),(6,11) in standard form?​

Mathematics
1 answer:
SIZIF [17.4K]4 years ago
7 0

ANSWER

The standard form is:

x - 2y =  - 16

EXPLANATION

The given line passes through (4,10)and (6,11).

The slope of this line is

m =  \frac{11 - 10}{6 - 4}

m =  \frac{1}{2}

The equation is given by the formula,

y-y_1=m(x-x_1)

We plug in the first point and the slope to get.

y-10= \frac{1}{2} (x-4)

2y - 20 = x - 4

x - 2y  =  - 20 + 4

x - 2y =  - 16

The standard form is

x - 2y =  - 16

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