Question

What is the equation of (4,10),(6,11) in standard form?​

Answer 1

ANSWER

The standard form is:

$x - 2y = - 16$

EXPLANATION

The given line passes through (4,10)and (6,11).

The slope of this line is

$m = \frac{11 - 10}{6 - 4}$

$m = \frac{1}{2}$

The equation is given by the formula,

$y-y_1=m(x-x_1)$

We plug in the first point and the slope to get.

$y-10= \frac{1}{2} (x-4)$

$2y - 20 = x - 4$

$x - 2y = - 20 + 4$

$x - 2y = - 16$

The standard form is

$x - 2y = - 16$