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spin [16.1K]
3 years ago
10

What is the greatest common factor of the terms of the polynomial below?

Mathematics
1 answer:
Savatey [412]3 years ago
7 0

Answer:

Step-by-step explanation:

What factors does 8A - 12х3 + 20х^2 have in common?  4 is the greatest factor common to 8, 12 and 20.

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X^(log_(\sqrt(x))(x-3))=4
Zina [86]

Answer:

X= -4

Step-by-step explanation:

3 0
3 years ago
Nononononononononono
Andrews [41]

Answer:

yesyesyesyes

Step-by-step explanation:

yesyesyesyesyes

3 0
3 years ago
Read 2 more answers
1. Given f(x)=2x 2 +1 and g(x)=3x-5 find the following
LenKa [72]

The value of the function 1) f -g = 2x² - 3x + 6 and 2) f(g(2)) is 3.

Here the two functions are given, f(x) and g(x).

f(x) = 2x² + 1

g(x) = 3x - 5

We have to find f-g and f(g(2)).

1) f- g

f(x) - g(x)

(2x² + 1) - ( 3x - 5)

2x² + 1 - 3x + 5

2x² - 3x + 6

2) f(g(2))

f(g(x)) = 2(3x-5)² + 1

         = 2( 9x² - 30x + 25) + 1

         = 18x² - 60x + 50 + 1

         = 18x² - 60x + 51

f(g(2)) = 18(2)² - 60(2) + 51

          =18× 4 - 120 + 51

          = 72 - 120 + 51

          = 123 - 120

          = 3

Therefore the value of f-g is 2x²- 3x + 6 and the value of f(g(2)) is 3.

To know more about the function refer to the link given below:

brainly.com/question/11624077

#SPJ4

     

4 0
1 year ago
Please help me on my math
s344n2d4d5 [400]

Answer:

m = -8

b = -24

Step-by-step explanation:

To solve this problem use the hint and put this equation in y = mx + b form. This is called slope-intercept form.

In slope-intercept form, the coefficient of x (which is m) is the slope of the line and b is the y-intercept of the line.

  • -32x - 4y = 96

Add 32x to both sides of the equation.

  • -4y = 32x + 96

Divide both sides of the equation by -4.

  • y = -8x - 24

Comparing this to y = mx + b, the -8 is "m" and -24 is "b". Therefore your final answers are:

m = -8

b = -24

5 0
3 years ago
Read 2 more answers
What is the solution set of [1/x-2]<-2
BigorU [14]

Answer:

  3/2 < x < 2

Step-by-step explanation:

We assume the problem is ...

  [tek]\dfrac{1}{x-2}<-2[/tex]

This will not be true for x-2 > 0 because that would make the left side positive. So, we must have x < 2, which makes the denominator negative. Multiplying by (x-2), we get ...

  1 > -2(x -2)

  1 > -2x +4

  2x > 3 . . . . . . add 2x-1

  x > 3/2

From above, we also have x < 2, so the solution set is ...

  3/2 < x < 2

7 0
4 years ago
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