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ikadub [295]
3 years ago
4

Describe the error in the work shown below. What is the correct product? The theater sold 562 tickets to the concert at a price

of $6 each. Use the distributive property to find the product of 6 × 562. 6(562) = 6(500) + (60)(2) = 3,120
Mathematics
2 answers:
user100 [1]3 years ago
7 0

Answer: The distributive property of this will be 6\times (500+62)=[(6\times 500)+(6\times 62)]=3372

Step-by-step explanation:

The tickets sold by the theater are 562 at a cost of $6 each, So to calculate the total cost, we multiply the number of tickets to the cost of one ticket.

Total cost = 6 × 562

By applying distributive property:

a\times (b+c)=[ab+ac]

Product of 6\times (500+62) will be:

6\times (500+62)=[(6\times 500)+(6\times 62)]=3372

Therefore, the total cost of the tickets will be $3372.

mel-nik [20]3 years ago
6 0

Answer: The number 562 should be written as 500 + 60 + 2. Then multiply each by 6 to get 6(500) + 6(60) + 6(2). Find the products and add. The correct answer is $3,372.

Step-by-step explanation:

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The admission fee at the steamboat springs hot air balloon festival is $1.50 for children and $4.00 for adults. On a certain day
GaryK [48]

Answer:

Number of child tickets =  800

Number of adult tickets = 330

Step-by-step explanation:

Let c = number of child tickets

and  a= the number of adult tickets.

We are given:

The admission fee at the steamboat springs hot air balloon festival is $1.50 for children and $4.00 for adults.

On a certain day, 1,130 enter the festival and 2, 520 is collected.

Making equations:

c+a=1130 (because total people entered are 1130, so adding number of adult and child tickets will give us total number of people)

1.50c+4.00a=2520  (because total money collected is 2520, so adding coat of adult and child tickets will give us total money)

Now, solving these equations simultaneously, we can find values of x and y

Let:

c+a=1130--eq(1)\\1.50c+4.00a=2520--eq(2)

From equation 1 find value of c and put it in eq(2)

c+a=1130\\c=1130-a

Putting value of c in eq(2)

1.50c+4.00a=2520\\Put\:c=1130-a\\1.5(1130-a)+4a=2520\\1695-1.5a+4a=2520\\-1.5a+4a=2520-1695\\2.5a=825\\a=\frac{825}{2.5}\\a=330

So, we get value of a = 330

Now, punting value of a in eq(1) to get value of c

c+a=1130\\c+330=1130\\c=1130-330\\c=800

So, we get value of c = 800

Therefore:

Number of child tickets = c= 800

Number of adult tickets = a = 330

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