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anastassius [24]
3 years ago
11

Is b a linear combination of a1, a2, and a3?

Mathematics
1 answer:
salantis [7]3 years ago
3 0
A1 = (1, -2 , 0) ; a2 = (0,1,2) ; a3 = (5,-6,8) ; b = (2,-1,6)

2*a1 = (2, -4,0)
3*a2 = (0, 3, 6)
-------------------
sum = (2, -1, 6) = b

Hope this helps

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Solve 5x^2 − 3x + 17 = 9.
Vedmedyk [2.9K]

Answer:

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = \frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}

or

x = \frac{3\pm\sqrt{9-160}}{10}

or

x = \frac{3+\sqrt{-151}}{10} and x = \frac{3-\sqrt{-151}}{10}

or

x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

here i = √(-1)

Hence,

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

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3 years ago
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What the answer to this
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Answer:

for which

Step-by-step explanation:

3 0
3 years ago
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