Answer:
(3x-4)(x-5)
Step-by-step explanation:
This is in the form
ax²+bx+c.
To factor this, we find factors of a·c that sum to b; this means factors of 3(20) = 60 that sum to -19:
60 = 1(60) or -1(-60); 2(30) or -2(-30); 3(20) or -3(-20); 4(15) or -4(-15); 5(12) or -5(-12); 6(10) or -6(-10). The only of these that sum to -19 are -4 and -15. This means we will split up -19x into -4x and -15x:
3x²-4x-15x+20
Next we group the first two terms and the last two terms:
(3x²-4x)+(-15x+20)
Factor out the GCF of each group. For the first group, this is x:
x(3x-4)
For the second group, this is -5:
-5(3x-4)
The common factor for these two groups is (3x-4):
(3x-4)(x-5)
Use a let statement
first
let x and x + 2 be the number so you write it like this
<u>let x = the first consecutive integer
</u><u>let x + 2 = the second consecutive integer
</u>
second
x(x+2)=323
x^2 + 2x = 323
-323 -323
x^2 + 2x -323 = 0
third
try to factor -323 so it is 19 and -17
(x + 19) (x - 17) = 0
x = 19
x = -17
hope this help
Answer:
-1
Step-by-step explanation:
y-1=-3
y=-2
.:1/2y=1/2(-2)=-1
Answer:
<u>Use Pythagorean theorem:</u>
#7
- 3² + 7² = 9 + 49 = 58
- (√57)² = 57
- 58 ≠ 57
- No
#8
- 11² + 2² = 121 + 4 = 125
- (5√5)² = 25*5 = 125
- 125 = 125
- Yes
<span>I believe that the answer would be -0.35416666666</span>