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kompoz [17]
3 years ago
15

Which equation represents the line that passes through the points (6,-3) and (-4,-9)?

Mathematics
1 answer:
Citrus2011 [14]3 years ago
7 0
I will give in y=mx+b and ax+by=c form

using point slope form
y-y1=m(x-x1)
where the slope is m and a point on that line is (x1,y1)

slope between 2 points (x1,y1) and (x2,y2) is (y2-y1)/(x1-x1)

given
(6,-3) and (-4,-9)
slope=(-9-(-3))/(-4-6)=(-9+3)/(-10)=-6/-10=3/5
a point is (6,-3)

y-(-3)=3/5(x-6)
y+3=3/5(x-6)
y+3=3/5x-18/5
y=3/5x-33/5
-3/5x+y=-33/5
3x-5y=33


equation is
y=3/5x-33 or
3x-5y=33 or
y+3=3/5(x-6) or
y+9=3/5(x+4)
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a) We use the rank-nullity theorem. First, note that 0 is an eigenvalue of algebraic multiplicity 1. The null space of B is equal to the eigenspace generated by 0. The dimension of this space is the geometric multiplicity of 0, which can't exceed the algebraic multiplicity. Then Nul(B)≤1. It can't happen that Nul(B)=0, because eigenspaces have positive dimension, therfore Nul(B)=1 and by the rank-nullity theorem, rank(B)=7-nul(B)=6 (B has size 7, see part e)

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3 years ago
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