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FinnZ [79.3K]
3 years ago
12

Jack cuts a pie into 4 equal parts. The pieces are called _______ of the pie​

Mathematics
2 answers:
djyliett [7]3 years ago
7 0
Fractions of the pie?
prohojiy [21]3 years ago
5 0

Answer:

the pieces are fourths or quarters

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Using the quadratic formula I can't remember what to do next <br>​
Advocard [28]

Answer: you square root it.

5r^2/5 = 80/5 =16

Sqr root of r^2=Sqr root of 16

r=4

Step-by-step explanation:

4 0
3 years ago
Determine if the following relation is a function or not
Darya [45]
1 is not. 2 is. 3 is not. 4 is. 5 is. 6 is. 7 is not. 8 is.
7 0
3 years ago
A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner
frozen [14]

Answer:

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner I_{corner} is:

I_{corner} = \int\limits \int\limits_R (x^2+y^2)  \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx

where :

(a and b are the length and the breath of the rectangle respectively )

I_{corner} =  \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx

I_{corner} =  \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx

I_{corner} =  \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}

I_{corner} =  \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Thus; the moment of inertia of the lamina about one corner is I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

7 0
3 years ago
A=10^x, b=10^yanda^y^*b*x=100then2xy=?​
sergejj [24]

Answer:

Here is your answer

Step-by-step explanation:

xy = 1

Hope you like it : )

7 0
3 years ago
Evaluate u + xy, if u = 18, x = 10, and y = 8. <br><br> A. 188<br> B. 36 <br> C. 98<br> D. 224
Luda [366]
If you would like to evaluate u + xy, you can do this using the following steps:

u = 18, x = 10, y = 8
u + xy = 18 + 10 * 8 = 18 + 80 = 98

The correct result would be C. 98.
7 0
3 years ago
Read 2 more answers
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