What about it? Specify please.
Plug the points into the equation.
Ex. y=3x-5
(X,y)
1. (5,10): 10=3(5)-5
15-5=10; point 1 is valid
-1=3(-2)-5
-1=-6-5
-1 does not equal -11
Point 2 is not valid
Same process for letter B
Ok so assuming the 0 means minus from typing problems
x^2-10x=-8
to completet the square
make sure the term in front of x^2 is 1
that is correct
then take 1/2 of the term in front of the x term and square it
-10/2=-5, (-5)^2=25
add that to both sides
x^2-10x+25=17
answer is the first equation
1.50 5/9(122-32)=5/9(90)= 50
I think the correct answer is C. Since a=πr², in order to get the area to become 1/4 of what it was previously, the radius needs to be cut in half to make the divide that side by 4. a=π(r/2)²=πr²/4 and will therefore multiply the area by 1/4.
