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zubka84 [21]
2 years ago
12

For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm

Mathematics
1 answer:
Paraphin [41]2 years ago
8 0

The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>

<u />

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

(\frac{14 \ mm}{7 \ mm})^{2}

= \frac{196 \ mm^{2} }{49\ mm^{2} }

=\frac{4}{1}

= 4:1

Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

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