A quadratic equation has the general form
of: <span>
y=ax² + bx + c
It can be converted to the vertex form in order
to determine the vertex of the parabola. It has the standard form of:
y = a(x+h)² - k
This can be done by completing a square. The steps are as follows:
</span><span>y = 3x2 + 9x – 18
</span>y = 3(x2 <span>+ 3x) – 18
</span>y + 27/4= 3(x2 <span>+ 3x+ 9/4) – 18
</span>y = 3(x2 + 3/2)^2 – 99<span>/4
</span>
Therefore, the first step is to group terms with the variable x and factoring out the coefficient of x^2.
Answer:
A) 83 km/ hour
B) 2/7 penalties / game
C) $16 / CD
D) 9 donuts / box
Step-by-step explanation:
A)
For this question they are asking for the distance traveled in 1 hour.
Since 747km was travelled in 9 hours, we divide 747 by 9 to find the distance travelled in 1 hour
747 ÷ 9 = 83
The unit rate is 83 km/ hour
B)
You have to find the number of penalties per game
Like before divide 10 by 35:
10 ÷ 35 = 10/35 = 2/7
2/7 penalties / game
C)
Find the cost of 1 CD :
64 / 4 = 16
$16 / CD
D)
Find the amount of donuts per box:
72/8 = 9
9 donuts per box
-Chetan K
The solution of 0.6(4-2x)=20.5-(3x+10) is x = 4.5
<u>Solution:</u>
Given, expression is 0.6 ( 4 – 2x ) = 20.5 – ( 3x + 10 )
We have to solve the above given equation for x.
Now, take the equation
![\rightarrow 0.6(4-2 x)=20.5-(3 x+10)](https://tex.z-dn.net/?f=%5Crightarrow%200.6%284-2%20x%29%3D20.5-%283%20x%2B10%29)
We have to use BODMAS rule. BODMAS means sequence of operations which is brackets, order, division, multiplication, addition and then subtraction
On solving the brackets, we get
![\rightarrow 0.6 \times 4-0.6 \times 2 x=20.5-3 x-10](https://tex.z-dn.net/?f=%5Crightarrow%200.6%20%5Ctimes%204-0.6%20%5Ctimes%202%20x%3D20.5-3%20x-10)
Now multiplication is given preference
![\rightarrow 2.4-1.2 x=10.5-3 x](https://tex.z-dn.net/?f=%5Crightarrow%202.4-1.2%20x%3D10.5-3%20x)
![\rightarrow 3 x-1.2 x=10.5-2.4](https://tex.z-dn.net/?f=%5Crightarrow%203%20x-1.2%20x%3D10.5-2.4)
Now subtraction is done
![\rightarrow 1.8 \mathrm{x}=8.1](https://tex.z-dn.net/?f=%5Crightarrow%201.8%20%5Cmathrm%7Bx%7D%3D8.1)
Now division is performed
![\rightarrow x=\frac{8.1}{1.8}=4.5](https://tex.z-dn.net/?f=%5Crightarrow%20x%3D%5Cfrac%7B8.1%7D%7B1.8%7D%3D4.5)
Hence, the value of x is 4.5
25 a² + 20 ab + 4 b²
for formula
![a^x+bx^ky^k+cy ^{2k }](https://tex.z-dn.net/?f=a%5Ex%2Bbx%5Eky%5Ek%2Bcy%20%5E%7B2k%20%7D%20)
find u,v such that: u.v = a
and u+v = b then group according to
![(ax ^{2k} +ux^ky^k)+(vx^ky^k+cy ^{2k} )](https://tex.z-dn.net/?f=%28ax%20%5E%7B2k%7D%20%2Bux%5Eky%5Ek%29%2B%28vx%5Eky%5Ek%2Bcy%20%5E%7B2k%7D%20%29)
=
![(25a^2+10ab)+(10ab+4b^2)](https://tex.z-dn.net/?f=%2825a%5E2%2B10ab%29%2B%2810ab%2B4b%5E2%29)
factor out 5a from :
![25a^2+10ab : 5a(2b+5a)](https://tex.z-dn.net/?f=25a%5E2%2B10ab%20%3A%205a%282b%2B5a%29)
factor out 2b from :
![10ab+4b^2: 2b(2b+5a)](https://tex.z-dn.net/?f=10ab%2B4b%5E2%3A%202b%282b%2B5a%29)
=
![5a(2b+5a) + 2b(2b+5a)](https://tex.z-dn.net/?f=5a%282b%2B5a%29%20%2B%202b%282b%2B5a%29)
factor out :
![(5a+2b)](https://tex.z-dn.net/?f=%285a%2B2b%29)
=
![(5a+2b)(5a+2b)](https://tex.z-dn.net/?f=%285a%2B2b%29%285a%2B2b%29)
Refine:
![(2b+5a)^2](https://tex.z-dn.net/?f=%282b%2B5a%29%5E2)
hope this helps!.
they have gathered 26 kilograms so far
Because they already had 2 kilograms before the new recycling plan ,and the new plan was to gather 1 kilogram each week and its been 24 weeks
So u just have to add the 24 kilograms +2 kilograms=26 kilograms