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drek231 [11]
3 years ago
14

FREEEEEEEEEEEEEEEEEE POINTSSSSSSSSSSSS​

Mathematics
1 answer:
kondor19780726 [428]3 years ago
3 0

Answer:

omg tanks u so much ^-^

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Rae planted a square garden that covers an area of 200 ft.² how many feet of fencing does he need to surround the garden
inessss [21]
To find this, first we have to find the square root of 200, which is about 14.14

Now we multiply 14.14 * 4 = 56.56

So Rae will need about 56.56 feet of fencing to surround the garden.
5 0
3 years ago
Sketch each line and find the slop and Y-intercept
Anon25 [30]
Lol where the problem
6 0
4 years ago
a 35 foot wire is secured from the top of a flagpole to a stake in the ground if the stake is 14 feet from the base of the flagp
zzz [600]
If my calculations are correct the answer is 21 ft
3 0
3 years ago
A balloon is blowing up at a constant rate of 9 cubic centimeters per second. When the volume of the balloon is 2048/3 pi cubic
jekas [21]

Answer:

\displaystyle \frac{dr}{dt}\approx 0,0112\ cm/sec

Step-by-step explanation:

<u>Rates of Change as Derivatives</u>

If some variable V is a function of another variable r, we can compute the rate of change of one with respect to the other as the first derivative of V, or

\displaystyle V'=\frac{dV}{dr}

The volume of a sphere of radius r is

\displaystyle V=\frac{4}{3}\pi r^3

The volume of the balloon is growing at a rate of 9\ cm^3/sec. This can be written as

\displaystyle \frac{dV}{dt}=9

We need to compute the rate of change of the radius. Note that both the volume and the radius are functions of time, so we need to use the chain rule. Differentiating the volume with respect to t, we get

\displaystyle \frac{dV}{dt}=\displaystyle \frac{dV}{dr}\displaystyle \frac{dr}{dt}

\displaystyle \frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}

solving for \displaystyle \frac{dr}{dt}

\displaystyle \frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2}

We need to find the value of r, which can be obtained by using the condition that in that exact time

\displaystyle V=\frac{2048}{3}\pi\ cm^3

\displaystyle \frac{2048}{3}\pi=\frac{4}{3}\pi r^3

Simplifying and isolating r

\displaystyle r^3=512

\displaystyle r=\sqrt[3]{512}=8\ cm

Replacing in the rate of change

\displaystyle \frac{dr}{dt}=\frac{9}{4\pi 8^2}

\displaystyle \frac{dr}{dt}=\frac{9}{256\pi }

\displaystyle \frac{dr}{dt}\approx 0,0112\ cm/sec

8 0
3 years ago
List the rst 10 terms of each of these sequences. a) the sequence obtained by starting with 10 and obtaining each term by subtra
vazorg [7]

Answer:

a) 10, 7, 4, 1, -2, -5, -8, -11, -14, -17.

c)  1, 2, 3 4 5 6 7 8 9 10.

d) √1 , √2, √3  √4 , √5, √6  √7 , √8, √9 √10.

e)     1, 5, 6, 11, 17, 28, 45, 73, 118, 191.

Step-by-step explanation:

a)  10, 10-3 , 10-3-3...

c)  3(1)- 2(1) , 3(2) - 2(2), 3(3) - 2(3),  3(4) - 2(4) ..

= 1, 2, 3, 4...

d) √1 , √2, √3 ...

e)  1, 5,  (5+6), (5 + 11)...

3 0
3 years ago
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