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icang [17]
4 years ago
11

Suppose we wish to test the hypotheses: H(o): u=15 H(1): u does not = 15 where we know that σ^2 = 9.0. If the true mean is 20, w

hat sample size must you choose to ensure that the probability of Type II error is no greater than 0.1?
Mathematics
1 answer:
Zepler [3.9K]4 years ago
8 0

Answer:

sorry

Step-by-step explanation:

i need points sorry dont know answer

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True or False ?
Gnoma [55]
True the answer is true babes :)
4 0
4 years ago
What percentage of the blocks is shaded in the picture?
emmasim [6.3K]
Hello! So the blocks are lined up in rows of 8. When you count the number of rows, there are 10 of them. 3 rows of 8 blocks are shaded out of 10 of them. That's 24 blocks shaded out of 80, because 8 * 10 is 80, and 3 * 8 is 24. Let's divide. 24/80 is 0.3.Let's multiply that by 100 to get it in percent form. 0.3 * 100 is 30. There. 30% of blocks are shaded in the picture.
7 0
3 years ago
Question is in attached file
Nonamiya [84]

The rate of the passenger train is 81.67 MPH and the rate of the freight train is 66.67 MPH.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have:

The distance traveled by passenger train = 245 miles

The distance traveled by freight train = 245 miles

The time takes for both trains is the same.

Let's suppose the rate of the passenger train is x and the rate of the freight train is y;

As we know,

Distance = speed×time

245/x = 200/y

200x = 245y

200x - 245y = 0 ..(1)

x = 15 + y ..(2)

Equations (1) and (2) represent the situation.

After solving equations (1) and (2):

\rm x=\dfrac{245}{3}= 81.67\\\\\\\:y=\dfrac{200}{3}=66.67

Thus, the rate of the passenger train is 81.67 MPH and the rate of the freight train is 66.67 MPH.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

5 0
2 years ago
4|w − 5| = 4
anastassius [24]

Answer:

   w = 9 or  w = 1

Step-by-step explanation:

4|w − 5| = 4

Divide both sides by 4

w - 5 = 4                         w - 5 = -4

   + 5    + 5                          + 5     + 5

     w = 9                             w = 1

7 0
3 years ago
PROBLEM 2<br> Evaluate 5x – – when x = 4 and y = 2.
krok68 [10]

Answer:

20

Step-by-step explanation:

1. substitute x for (4)

2. multiply 5(4)

3. The answer is 20

5 0
4 years ago
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