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e-lub [12.9K]
3 years ago
9

X+3/12=2/7 plz show work

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
5 0
35714286/1000000000, simplified is <span>17857143/500000000.</span>
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a counter top is in the shape of a trapizoid . the lengths of the base is 70 1/2 and 65 1/2 inches long. the area of the counter
Grace [21]
I attached a photo of the work below :-) 

Area of a trapezoid= [(a+b)÷2]h
1,224 in²= [(65.5 in+70.5in)÷2]h
1,224in²= (136÷2)h
1,224 in²= 68h
(1,224 in²÷68)= 68h÷68 (elimination)
h= 18 inches

4 0
3 years ago
Find the exact value of (1 7/9)^1/2
sweet [91]

I assume you mean the mixed number 1 + 7/9.

As an improper fraction, we have

1   7/9 = 1 + 7/9 = 9/9 + 7/9 = (9 + 7)/9 = 16/9

Then the square root of this is

√(1   7/9) = √(16/9) = √(4²/3²) = √((4/3)²) = 4/3

3 0
2 years ago
Please answer quick I have a lot of work to do :C
NeTakaya

Answer:

A

Step-by-step explanation:

I hope its correct! :)

4 0
3 years ago
Geometry math question please help
Phoenix [80]
Therefore,DE=4y-8=4*6-8=16
And ,BE=y+10=6+10=16
=>BD=DE+EB=16+16=32
Hope This helps u...!!

7 0
3 years ago
The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.
valina [46]

Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.85}{2} = 0.075

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.075 = 0.925, so Z = 1.44.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that \sigma = \sqrt{1.69} = 1.3

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

A sample of n is needed, and n is found for M = 0.14. So

M = z\frac{\sigma}{\sqrt{n}}

0.14 = 1.44\frac{1.3}{\sqrt{n}}

0.14\sqrt{n} = 1.44*1.3

\sqrt{n} = \frac{1.44*1.3}{0.14}

(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2

n = 178.8

Rounding up

A sample of 179 is needed.

7 0
3 years ago
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