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3 years ago

Find the value of x in each case:

Mathematics

2 answers:

pickupchik [31]3 years ago

8 0

Answer: X = 15

Step-by-step explanation: 5x and the angle next to 9x would be equal to 8x and 5x and the angle next to 8x would be equal to 9x. So the angles that are not given would be 4x and 3x. If you add all of the angles up inside the triangle (5x + 4x + 3x) it equals 12. A triangle has 180 degrees so we have to divide 180 by 12 which comes out to ***15***

kicyunya [14]3 years ago

7 0

I think the value of x is 15

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Alecsey [184]

X=32

All triangles add up to 180 degrees so if the right angle is 90 degrees then you have 90 degrees left. Next, you take the 2x and x-6 and plug them into the equation 3x-6=90. Once you solve that you get x=32.

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3 years ago

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djverab [1.8K]

Answer:

Step-by-step explanation:

30% off of $18.00

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3 years ago

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eduard

Answer:

25% decrease

Step-by-step explanation:

Take the original amount of books and subtract the new number of books

20 -15 = 5

Divide by the original amount of books

5/20 = .25

Multiply by 100%

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3 years ago

What is this figure Please answer fast

lyudmila [28]

Answer:

Hexagonal prism

Step-by-step explanation:

Since the base is a hexagon (six sided shape) and there are two of them, it is considered a prism. This is an Hexagonal prism.

Do not confuse it with hexagonal pyramid because:

1) It does not look like a pyramid

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4 0

3 years ago

Read 2 more answers

The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to

Firdavs [7]

Rewrite the boundary lines y = -1 - x and y = x - 1 as functions of y :

y = -1 - x ==> x = -1 - y

y = x - 1 ==> x = 1 + y

So if we let x range between these two lines, we need to let y vary between the point where these lines intersect, and the line y = 1.

This means the area is given by the integral,

$\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy$

The integral with respect to x is trivial:

$\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy$

For the remaining integral, integrate term-by-term to get

$\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}$

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line y = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

6 0

3 years ago