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3 years ago

9

Find the surface area of a sphere with radius of 60 centimeters. Leave your answer in terms of pi

1 answer:

Gre4nikov [31]3 years ago

7 0

Answer:

14400π

<h2>Step-by-step explanation:</h2>

Surface Area = 4πr²

= 4×π×602

= 14400π

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What is the second step in the construction?

MrMuchimi

Answer:

To draw the perpendicular bisector of any line segment, the compass opening should be the kept constant at any value a little more than half the length of the line segment. Then the compass point should be kept on one end and arcs drawn above and below and then keeping the same compass opening the same as mentioned before, the compass point should be placed on the other end and the arcs should be drawn above and below the segment touching the previous arcs.

Thus, out of the given options, the first option best suits the next step Herberto should take.

Step-by-step explanation:

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3 years ago

H²=p²+b² make b the subject of formula

zubka84 [21]

Answer:

done same as before put value and do process like simplify

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2 years ago

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Help plsss A sign in a bakery gives these options: 12 cupcakes for $29, 24 cupcakes for $56, and 50 cupcakes for $129 a) Find ea

xxTIMURxx [149]

Answer:

A) $2.42, $2.33, $2.58

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Step-by-step explanation:

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2 years ago

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago

2p x 3q x 5r maths watch

Zepler [3.9K]

Answer:

2px^ 8 qr

Step-by-step explanation:

<u>Reformatting the input : </u>

Changes made to your input should not affect the solution:

(1): "x5" was replaced by "x^5". 1 more similar replacement(s).

<u>STEP 1 : </u>

<em><u>Equation at the end of step 1 </u></em>

((2px3 • q) • x5) • r

<u>STEP 2 : </u>

<u></u>

<em><u>Final result : </u></em>

2px8qr

<u><em>HOPE THIS HELPS!</em></u>

<u><em> PLEASE MARK BRAINLIEST IF THIS HELPED YOU LEARN! :)</em></u>

3 0

3 years ago

Read 2 more answers