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leonid [27]
3 years ago
8

Putting recipe makes 4 1/2 cups of pudding. How many 1/3 cup servings does this equal?

Mathematics
2 answers:
Harrizon [31]3 years ago
5 0

The correct answer is C. 13 1/2

Because... you just have to divide 4 1/2 by 1/3 so you change 4 1/2 to it’s improper fraction which is 9/2 then you divide it like this- 9/2 / 1/3 = (do the keep change flip method) 9/2 x 3/1 which equals to 27/2

Then you divide 27 by 2 and then it gets you your answer which is 13 1/2

Hope this helps! :)

mel-nik [20]3 years ago
4 0

Answer:

C

Step-by-step explanation:

First, write 4 ½ in improper form.  2 × 4 + 1 = 9. So the fraction is 9/2.

Now divide:

9/2 ÷ 1/3

To divide by a fraction, multiply by the reciprocal:

9/2 × 3/1

27/2

13 1/2

Answer C.

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3 years ago
Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below.
garik1379 [7]

Answer:

The 95% confidence interval would be given by 0.281 \leq \mu_1 -\mu_2 \leq 0.529  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =9.2 represent the sample mean 1

\bar X_2 =8.8 represent the sample mean 2

n1=27 represent the sample 1 size  

n2=30 represent the sample 2 size  

\sigma_1 =0.3 population standard deviation for sample 1

\sigma_2 =0.1 population standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

Solution to the problem

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =9.2-8.8=0.4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that t_{\alpha/2}=1.96  

Now we have everything in order to replace into formula (1):  

0.4-1.96\sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}=0.281  

0.4+1.96\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=0.519  

So on this case the 95% confidence interval would be given by 0.281 \leq \mu_1 -\mu_2 \leq 0.529  

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Answer:

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Step-by-step explanation:

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Lyrx [107]

Answer:

1 or 100%.

Step-by-step explanation:

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