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icang [17]
3 years ago
13

Does the point (6, 0) satisfy the equation y = x2?

Mathematics
2 answers:
Nataly_w [17]3 years ago
7 0

Answer:

No, point (6, 0) is not on the equation.

Step-by-step explanation:

To do this question the easiest way, you would use your scientific/graphing calculator and type in your equation. But you can do this with your mind.

Since the equation y = x^2 does not have any number in it (such as m = slope) it does not start anywhere. You will put it in the origin which is (0, 0) from there, you can tell that the equation will not reach (6, 0), but only (1, 1).

shtirl [24]3 years ago
6 0

Replace x in the equation with the x value of the point (6) and solve. If it equals the y value (0) it is a solution if it noes not equal (0) it is not a solution.

Y = 6^2 = 36

36 is not 0 so (6,0) is not a solution

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Find the area. Round to the nearest tenth.<br>6 in.<br>5 in.<br>9 in.<br>in.<br>​
ycow [4]

Answer:

131 1/4 in.²

Step-by-step explanation:

To find the area of the figure, you would have to divide the figure into two parts.  The figure can be divided into two rectangles.

<u>Rectangle 1</u>

The length is 11 3/4 in.  The width is 6 in.

A = lw

A = (11 3/4 in.)(6 in.)

A = 70 1/2 in.²

<u>Rectangle 2</u>

The length is 9 in.  The width is 6 3/4 in.

A = lw

A = (9 in.)(6 3/4 in.)

A = 60 3/4 in.²

Add the two areas together.

70 1/2 in.²  +  60 3/4 in.²  =  131 1/4 in.²

7 0
3 years ago
The axis of symmetry for the graph of the function is f(x) = x2 + bx + 10 is x = 6. What is the value of b?
joja [24]

Answer:

b=-12

Step-by-step explanation:

we have

f(x)=x^{2}+bx+10

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2} +k

where

(h,k) is the vertex of the parabola

and the axis of symmetry is equal to x=h

In this problem we have the axis of symmetry x=6

so

the x-coordinate of the vertex is equal to 6  

therefore

For x=6+1=7 -----> one unit to the right of the vertex

Find the value of f(7)

f(7)=7^{2}+b(7)+10

f(7)=59+7b

For x=6-1=5 -----> one unit to the left of the vertex

Find the value of f(5)

f(5)=5^{2}+b(5)+10

f(5)=35+5b

Remember that

f(5)=f(7) ------> the x-coordinates are at the same distance from the axis of symmetry

so

59+7b=35+5b ------> solve for b

7b-5b=35-59

2b=-24

b=-12


3 0
3 years ago
Read 2 more answers
Factor out the greatest common<br> factor: -16x? + 12x?
svlad2 [7]

Answer:

4x is the greatest common factor of those two.

Step-by-step explanation:

(-16x + 12x)

4x (-4 + 3)

4x is the GCF

Why you may ask is 4x the GCF because when you divide 4x from both you're left with -4 + 3...... you can't take out the negative from the 16 because when you check your work negative 4x times 3 gives you negative 12x which isn't the equation you started with. So positive 4x times 3 give you 12x.

Hopes this helps!!!

7 0
3 years ago
Can someone actually help me please?
Tamiku [17]
D and B is the anwser
5 0
2 years ago
Just help me out with this polynomial i need help <br> { -m^{2} + 6} + { -4m^{2} + 7m + 2} =
PolarNik [594]

Answer:

-5m^2+7m+8

Step-by-step explanation:

Here, we add up two polynomials shown.

The polynomials are:

[-m^2 + 6]+[-4m^2 +7m + 2]

In order to add up the 2 polynomials shown, we have to see the "like terms" and add them up.

We add up the "m^2" terms and the constant (number) terms. There is one term with "m", so we leave it like that. Let's add up. Shown below:\

[-m^2 + 6]+[-4m^2 +7m + 2]\\=-m^2-4m^2+6+2+7m\\=-5m^2+7m+8

This is the sum of the 2 polynomials shown:  -5m^2+7m+8

7 0
3 years ago
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