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3 years ago

7

12 less than 7 times a number x

1 answer:

erma4kov [3.2K]3 years ago

8 0

The answer is 5x because when you do the math 12 subtracted by 7 equals 5 then you add the x at the end.

You might be interested in

Find X please.......

nikdorinn [45]

So Angle 5 = 1x - 7 and angle 2 = -2x + 18. You can work out that angle 1 is the same as angle 5 because corresponding angles are equal. Then you know that angle 1 + angle 2 = 180 because angles on a straight line add to 180. So therefore 1x - 7 -2x + 18 = 180 so -1x + 11 = 180 so -x = 169 so x = -169. Hope this helps :)

8 0

3 years ago

Helen is putting a fence around her flower garden, which is in the shape of half of a circle and a rectangle. If the semicircle

erastova [34]

Answer:

Part 1) Helen will need 38 feet of fencing

Part 2) The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) The approximate distance around half of the circle is 11 feet

Step-by-step explanation:

Part 1) How much fencing will Helen need?

Find out the perimeter

we know that

The perimeter of the figure is equal to the sum of three sides of the rectangular section plus the circumference of a semicircle

so

$P=2L+W+\frac{1}{2}\pi D$

we have

$L=10\ ft\\W=7\ ft\\D=7\ ft\\\pi =\frac{22}{7}$

substitute

$P=2(10)+7+\frac{1}{2}(\frac{22}{7})(7)$

$P=20)+7+11=38\ ft$

therefore

Helen will need 38 feet of fencing

Part 2) What is the perimeter around the three sides of the rectangular section of the garden?

$P=2L+W$

we have

$L=10\ ft\\W=7\ ft$

substitute

$P=2(10)+7$

$P=20+7=27\ ft$

therefore

The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) What is the approximate distance around half of the circle?

Find the circumference of semicircle

$C=\frac{1}{2}\pi D$

we have

$D=7\ ft\\\pi =\frac{22}{7}$

substitute

$C=\frac{1}{2}(\frac{22}{7})(7)$

$C=11\ ft$

therefore

The approximate distance around half of the circle is 11 feet

4 0

2 years ago

Read 2 more answers

I theater sells tickets for a concert. Tickets for lower-level seats sell for $35 each and tickets for upper-level seats sell fo

lora16 [44]

Let X= the number of tickets sold at $35 each

Let 350 -X = the number of tickets sold at $25 each

The number of tickets sold for each type will be computed as follows:

X(35)+(350-X)25=10250

35X+8750-25X=10250

10X=10250-8750

X=1500/10

X=150 the number of tickets sold at $35 each

350-150 the number of tickets sold at $25 each

To recheck:

150(35)+200(25)

5250+5000

10250

7 0

2 years ago

PLS HELP ASAP THIS IS DUE SOON... WHOEVER ANSWERS FIRST WILL BE MARKED AS BRAINLYEST!!!!

Maru [420]

Answer:

40m^2 152.6m^2

Step-by-step explanation:

7 0

3 years ago

If the crab 5ft below sea level and the cliff is 3ft above the sea level what is the distance between them?

xz_007 [3.2K]

8ft is the dstance between them.

5+3 = 8

7 0

3 years ago