∠13 = 70.5° [Vertically Opposite angles]
∠13+∠14=180° [Linear pair]
70.5°+∠14=180°
∠14=180-70.5
∠14=109.5
∠15=∠14=109.5 [Vertically opposite angles]
∠13=∠12= 70.5° [Co-interior angles]
∠12=∠10= 70.5° [Vertically Opposite angles]
∠14=∠11=109.5 [Co-interior angles]
∠9=∠11= 109.5 [Vertically opposite angles]
∠13=∠7= 70.5° [Alternate interior angles]
∠7=∠5=70.5° [Vertically Opposite angles]
∠7+∠8=180° [Linear Pair]
70.5+∠8=180
∠8=180-70.5
∠8=109.5°
∠8=∠6= 109.5° [Vertically Opposite angles]
∠6=∠3=109.5° [Co-interior angles]
∠7=∠2=70.5° [Co-exterior angles]
∠2=∠4= 70.5° [Vertically Opposite angles]
∠3=∠1= 109.5° [Vertically Opposite angles]

<h3>Measures of all angles in sequence⤵️</h3>
- ∠1= 109.5°
- ∠2= 70.5°
- ∠3= 109.5°
- ∠4= 70.5°
- ∠5= 70.5°
- ∠6= 109.5°
- ∠7= 70.5°
- ∠8= 109.5°
- ∠9= 109.5°
- ∠10= 109.5°
- ∠11= 70.5°
- ∠12= 109.5°
- ∠13= 70.5°
- ∠14= 109.5°
- ∠15= 109.5°
- ∠16= 70.5°
A- 1gb=3$ 30$+(3*gb used)= total
B- 30$+(3*10)= 60$
If George completed 3/5 of work in 9 days, it means that he needs 3 days to finish 1/5th of the work.
The remaining part is 2/5 because 1-3/5=2/5. 2/5 is also 6/15
From this, how much did George do? in the first 3 days he did 1/5th and then one more day was left, during which he did 1/5/3=1/15th.
So he did in total 1/15+1/5=1/15+3/15=4/15.
this means that Paul did the rest of 6/15, so Paul did 6/15-4/15=2/15.
So we know that he does 2/15 in 4 days, which means that every two days he can do 1/15 of the work
so he would need 15 times 2 days to finish the work - 30 days!