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2 years ago

X to the third plus x minus 7 equals -3 square root of x - 1

Mathematics

1 answer:

Ugo [173]2 years ago

5 0

Answer:

x ≈ 1.5004

Step-by-step explanation:

We suppose your equation is ...

$x^3+x-7=-3\sqrt{x-1}$

Squaring both sides and subtracting the right side gives ...

$x^6 +2x^4 -14x^3 +x^2 -23x +58 = 0$

This 6th-degree equation has two positive real roots, near x=1.5, and x=2. The root at x=2 is extraneous. The one near x=1.5 is irrational.

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sleet_krkn [62]

Answer:

I believe the answer is C. 0.75

Step-by-step explanation:

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3 years ago

Can someone help me please????

liraira [26]

Let X be the random variable denoting the number of successful throws.

Here X~ Binomial Distribution with n = 5 and p = 0.80.

the probability of her missing 3 (or more) free throws out of 5

= P ( X ≤ 2)

= P (X= 0) + P(X= 1) + P(X= 2)

=0.00032 + 0.0064 + 0.0512
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= 0.05792

I hope my answer has come to your help. God bless and have a nice day ahead!
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3 years ago

Read 2 more answers

Working alone, Darryl can oil the lanes in a bowling alley in ten hours. Ming can oil the same lanes in eight hours. Find how lo

GenaCL600 [577]

Answer:

9.1

Step-by-step explanation:

8 0

2 years ago

madeline studies honeybees. every week she weighs the same honeybee hive, the first week the hive weighs 11.607 kilograms. its w

fomenos

So, we already know that one hive has a weight of 11.607kg and .204kg is add each week, so we add on .204kg times, w, representing weeks onto 11.607kg and our t is our total of weight of a hive with respect to weeks

$w = weeks \\ t = total \: weight \: with \: respect \: to \: weeks$
So in this case our w is 7.5 weeks and now we evaluate t

$w = 7.5 \: weeks \\ t = ?$
Solve
$11.607kg + .204kg(w) = t \\ 11.607kg + .204kg(7.5) = t \\ t = 13.137kg$
Answer:

Hive's weight will increase by 1.53kg in 7.5 weeks to 13.137kg

6 0

3 years ago

Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4%

bogdanovich [222]

Mr. Jackson invested $800 at 6% per year and $ 2400 at 4 % per year

<h3><u>Solution:</u></h3>

Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.

Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively

Also, his annual return totaled $144

We can form following equation on the basis of question:-

$\begin{array}{l}{\text { Then, } \frac{a \times 6 \times 1}{100}+\frac{3 a \times 4 \times 1}{100}=\$ 144} \\\\ {\frac{6 a}{100}+\frac{12 a}{100}=144} \\\\ {\frac{6 a+12 a}{100}=144} \\\\ {\frac{18 a}{100}=144} \\\\ {18 a=14400} \\\\ {a=14400 \div 18}\end{array}$

a = $800

The amount of money invested at 6% = a = 800

The amount of money invested at 4 % = 3a = 3(800) = 2400

So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400

4 0

2 years ago