Before the driver applies the brakes ( with the reaction time ):
d 1 = v0 · t = 20 m/s · 0.53 s = 10.6 m
After that:
v = v0 - a · t1
0 = 20 m/s - 7 · t1
7 · t1 = 20
t1 = 2.86 s
d 2 = v 0 · t1 - a · t1² / 2
d 2 = 20 m/s · 2.86 s - 7 m/s² · (2.86 s)²/2 = 57.2 m - 28.6 m = 28.6 m
d = d 1 + d 2 = 10.6 m + 28.6 m = 39.2 m
Answer: the stopping distance of a car is 39.2 m.
Answer: 9 x 
Step-by-step explanation:
Common Fractions with Decimal and Percent<span> Equivalents ... </span>5/9<span>, 0.555… ... Tables and Formulas · Common Repeating Decimals and Their </span>Equivalent<span> Fractions ...</span>
Answer:
v= -1
Step-by-step explanation:
5+2v=3
2v=3-5
2v= -2
v= -2/2
v= -1
there is a 50% chance of landing on either heads or tails
