If they are connected exactly as shown, nothing can happen.
Answer:
Alice Distance = 100 meters
Peter's Distance = 3 km
Alice Displacement and Peter's displacement are both 100 meters upwards.
Explanation:
To solve this question, we have to first define distance and displacement.
Distance is simply the measurement of the sum of all paths travelled from one point to another while displacement is measurement of the shortest distance from initial point to final point.
Now, Alice and Peter are moving from the same point.
Alice distance travelled is 100 meters.
Also, her displacement will be 100 meters because it is the shortest distance to the summit of the cliff.
Now, for Peter, he decides to take a longer route which is 3 km in distance.
However, the shortest path which is the displacement is still 100 meters.
Thus, Peter's displacement is 100 meters.
Answer:
1.029
Explanation:
1.0090 can also be looked at as "1.009"
0.02 can also be looked at as "0.020"
I think of it as 20+9 which is 29. There for your answer should be 1.029. There are no measurement rules applying to this equation since they are both in centimeters. So you don't have to convert anything.
When it says something like 'on the verge of moving,' it means that the pulling force and static friction force and gravitational force all cancel out! Any more pulling force and it is ready to move!
At some point, you want F as a function of <span>μs</span>, to determine the force needed depending on the coefficient of static friction. This function, <span>F(<span>μs</span>)</span>, will rely on the angle θ as well, but we want to consider just one angle θ in every scenario. One value means it is constant.
But if we know the F, and we know <span>μs</span>, we can find what the constant angle θ must be!
If F is the pulling force, <span>FS</span> is the static friction force, and <span>FG</span> is gravitational force,
<span><span><span>Fnet</span>=0</span><span>=F+<span>FS</span>+<span>FG</span></span><span>=F+<span>FN</span><span>μs</span>+mgsinθ</span><span>=F+mgcosθ<span>μs</span>+mgsinθ</span><span>=0</span></span>
Then you can find <span>F(<span>μs</span>)</span>, but then there is the issue of solving for the θ<span> to make it true.</span>
Answer:
(a)
(b) 157.76679 m
(c) 17.62757 m/s
Explanation:
Net force acting,
Acceleration, where m is the mass
(b)
From kinematic equation
where s is displacement, u is initial velocity, t is time taken and a is acceleration.
Considering that u=0 since it starts at rest
and substituting the value of a as calculated in part a, t is 17.9 s hence
(c
)
From kinematic equation
v=u+at where u and v are initial and final velocities respectively, a is acceleration and t is duration in seconds. Since it starts from rest, u=0 and substituting the value of a as found in part a, t given as 17.9 s we get
V=0+0.984781*17.9=17.62757 m/s